Hey can anyone help with this question?
1 answer:
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Answer:
D. Kelsey graphed the slope as the y-intercept and the y-intercept as the slope.
Step-by-step explanation:
The equation to graph was : y= 3x + 1 where the slope is 3 and the y-intercept is 1
However, Kelsey graph line passes through points (-3, 0)and (0, 3).From these points the equation of the line is;
m=Δy/Δx where
m=the slope of the graph
Δy= 3-0 =3
Δx= 0--3 =3
m=3/3 = 1
The equation of the line should be;
m=Δy/Δx
1=y-3/x-0
1x= y-3
3+1x= y
y= 1x + 3 ----------where the slope is 1 and y-intercept is 3
So you can see here that in the original equation,<em> the slope m is 3 and y-intercept is 1 as shown in the first attached graph.</em>
While in the Kelsey's graph, <em>the slope is 1 and the y-intercept is 3 as in the second attached graph. </em>
<em>Thus, the correct answer is D : Kelsey graphed </em><u><em>the slope,3</em></u><em> as the </em><em>y-intercept </em><em>and the</em><u><em> y-intercept,1,</em></u><em> as the slope. </em>
Answer choice A is incorrect because Kelsey didnot graph the y-intercept, 1 on the x-axis but graphed point (-3,0) on the x-axis.
Answer choice B is incorrect because on Kelsey's equation the y-intercept is 3 and not -3. i.e. y=1x + 3
Answer choice C is incorrect because Kelsey graphed the slope as up 1 right 1 which is okay per the equation , y=1x+3.However, this incorrect because the correct graph has a slope of 3.
