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Roman55 [17]
3 years ago
6

What do cos and sin mean?

Mathematics
1 answer:
Mademuasel [1]3 years ago
8 0

Answer and Step-by-step explanation:

These two terms (pronounced as Sine and Cosine) are used to solve for the sides and angles of a triangle in Trigonometry.

They are functions revealing the shape of a right triangle.

Sine is a trigonometric function of an angle. The sine of an acute angle is defined in the context of a right triangle: for the specified angle, it is the ratio of the length of the side that is opposite that angle, to the length of the longest side of the triangle.

Cosine is also a trigonometric function of an angle. The cosine of an angle is the relation of the length of the side that is adjacent that angle, to the length of the longest side of the triangle.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

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Mai had $14.50 she spent $4.35 at the snack bar and $
Shalnov [3]

Answer:

Mai has <u>$4.90</u> left

Step-by-step explanation:

14.50 - 4.35 - 5.25= 4.9

4 0
3 years ago
Read 2 more answers
10/27 x (3/8 divided by 5/24) =
pantera1 [17]

Answer: 1/864 =0.00116

Step-by-step explanation: simplify 3/8

divide 3/8 by 5= 3/40

3/40 divided by 24 =1/720

10/27 X 1/320= 1/864

simplify 10/27 and get 1/864 as a fraction but in a decimal 0.00116

 

4 0
3 years ago
What is 3 divde by 3/4​
Alex17521 [72]

\bf 3\div \cfrac{3}{4}\implies \cfrac{3}{1}\div\cfrac{3}{4}\implies \cfrac{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{1}\cdot \cfrac{4}{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies 4

8 0
3 years ago
A cylindrical oil drum has a diameter of 2 feet and a height of 3 feet. What is the volume of the oil drum?
bixtya [17]

cylindrical volume

=  \pi{r}^{2} h

Radius of the cylindrical

2ft ÷ 2 = 1.5ft

3.142 \times  {1.5}^{2}  \times 3 \\  = 3.142 \:  \times 2.25 \times 3  \\   = 7.0695 \times 3 \\ =  21.2085 \\  = 21.21(2d.p.)

3 0
3 years ago
Identify the zeros of the function f(x) =2x^2 − 2x + 13 using the Quadratic Formula. SHOW WORK PLEASE!! I NEED HELP!!
TiliK225 [7]

Answer:

The zeros of the given function are not real. The zeros of the function is at :

x=\frac{1}{2}+\frac{5i}{2}    and  x=\frac{1}{2}-\frac{5i}{2}

Step-by-step explanation:

Given quadratic function:

f(x)=2x^2-2x+13

To  find the zeros of the function using quadratic formula.

Solution:

Applying quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

For the given function:

a=2, b=-2\ and\ c=13

Thus, we have:

x=\frac{-(-2)\pm\sqrt{(-2)^2-4(2)(13)}}{2(2)}

x=\frac{2\pm\sqrt{4-104}}{4}

x=\frac{2\pm\sqrt{-100}}{4}

x=\frac{2\pm\sqrt{100}i}{4}

x=\frac{2\pm10i}{4}

x=\frac{2+10i}{4}      and  x=\frac{2-10i}{4}

x=\frac{2}{4}+\frac{10i}{4}   and  x=\frac{2}{4}-\frac{10i}{4}

x=\frac{1}{2}+\frac{5i}{2}    and  x=\frac{1}{2}-\frac{5i}{2}

Thus, the zeros of the given function are not real. The zeros of the function is at :

x=\frac{1}{2}+\frac{5i}{2}    and  x=\frac{1}{2}-\frac{5i}{2}

4 0
3 years ago
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