Answer: 8:9
Step-by-step explanation: Two find this answer, you need to see what will be the greatest number they can divide by (greatest common divider), it needs to be the same number for both 18 and 16. What number can go into both numbers, and is the greatest number? The answer is two, now you divide 2 by 18 and 16, so you'll get 8:9.
Hope this helps have a BLESSED and wonderful day! :-)
-Cutiepatutie
Solutions
To solve this problem we have to use the Pythagorean theorem. You can only use the Pythagorean theorem in Right Triangles. The longest side of the triangle is called the "hypotenuse". C² is the longest side so it is the hypotenuse . To calculate c² we have to do α² + β² = c².
Given
One leg of a right triangular piece of land has a length of 24 yards. They hypotenuse has a length of 74 yards. The other leg has a length of 10x yards.
First leg (24 yards) would be α
Second leg would be β
Hypotenuse (74 yards) would be c
Now we have points α β c.
a² (24) + β² ( x ) = c² (74)
Calculations
c² = α² + β²
74² = 24²+ β²
<span>5476 = 576 + </span>β²
5476 - 576 = β²
<span> </span>
<span>4900 = </span>β²
→√4900
<span> </span>
β<span> = 70 yards
</span>
<span>70 = 10x
</span>
<span>x = 70</span>÷<span>10 = 7 yards
</span>
The second leg = 7 yards
Answer:
b = (c - 3a)/4
Step-by-step explanation:
3a + 4b = c
4b = c - 3a
b = (c - 3a)/4
She walked the most on Friday because you have to find the LCD. The LCD is 24.
For example, to change the denominator of 4 to 24, you must divide 24 divided by 4 which equals 6. Since your answer was 6, you have to multiply both numbers, which are 3 and 4, by 6.
So, 4 times 6 is 24. This is the denominator and 4 times 3 is 18. This is the numerator.
If you do the same with all of the fractions then you will have the fractions of, 18 over 24, 12 over 24, and 9 over 24.
Look at all the numerators (the number on top of the fraction) and decide which one is the biggest.
18 is the biggest and since the fraction 18 over 24 was originally 3 over 4, this means that she walked the most on Friday.
Hoped this helps!!
Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
