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igomit [66]
4 years ago
11

Will calculators or computers be needed to perform some calculations?

Mathematics
2 answers:
STatiana [176]4 years ago
7 0
I think the answer would be no. We create computers so we can do the problems ourselves. maybe eventually the asnwer will be yes, but for now i think they just solve equations quicker than the average human brain. hope this helps!
yulyashka [42]4 years ago
6 0

Answer:

yes

Step-by-step explanation:

When performing certain statistical calculations, finding roots, or working with powers, calculators or computers are necessary for the calculations; otherwise, more traditional methods will be sufficient.

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How many centimeters are in 5 inches? 1in. = 2.54 cm<br><br> 5 in. = ?
Aleks [24]
It is very simple the answer is 12.7 cm
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Hope it helps : )
6 0
3 years ago
1/4 = 8/k HELP! WILL GIVE BRAINLIST IF CORRECT ANSWER SND CORRECT FORMAT
gtnhenbr [62]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Please answer
SVEN [57.7K]

From the calculation done below, it can be seen that the cost of one orange is 85 cents.

<h3>How do we determine the cost of a product?</h3>

The cost of one orange can be determined as follows:

One dime = 10 cents

2 dollars = 200 cents

Total amount given by Sue to the store clerk = One dime + 2 dollars = 10 cents + 200 cents = 210 cents

Cost of two oranges = Total amount given by Sue to the store clerk –

Change = 210 cents – 40 cents = 170 cents

Cost of one orange = Cost of two oranges / 2 = 170 cents / 2 = 85 cents

Learn more about cost here: brainly.com/question/14844899.

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7 0
2 years ago
When x = 5 and y = 6, x2 + 3(x+y)= (Type an integer<br> or a decimal
Marta_Voda [28]

Answer:

43

Step-by-step explanation:

We are given everything we need, all you need to do is plug in <u>5 for x</u> and <u>6 for y.</u>

(5)2 + 3(5+6) =

= 10 + 3(11)

= 10 + 33

= 43

6 0
3 years ago
Need answer ASAP will give BRAINLEST <br><br> Please put a full answer thank you
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Answer:
1. It means they saved $125 in 10 months
2. y = 25/2
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2 years ago
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