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ddd [48]
2 years ago
10

Please answer

Mathematics
1 answer:
SVEN [57.7K]2 years ago
7 0

From the calculation done below, it can be seen that the cost of one orange is 85 cents.

<h3>How do we determine the cost of a product?</h3>

The cost of one orange can be determined as follows:

One dime = 10 cents

2 dollars = 200 cents

Total amount given by Sue to the store clerk = One dime + 2 dollars = 10 cents + 200 cents = 210 cents

Cost of two oranges = Total amount given by Sue to the store clerk –

Change = 210 cents – 40 cents = 170 cents

Cost of one orange = Cost of two oranges / 2 = 170 cents / 2 = 85 cents

Learn more about cost here: brainly.com/question/14844899.

#SPJ1

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kondor19780726 [428]

Answer:

I'm sorry but if your struggling with this iďk what to tell you chief

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En la biblioteca hay 400 libros. Si el 25% son de matemáticas. Cuantos libros de matemáticas hay?
Romashka [77]

Answer:

100.

Step-by-step explanation:

25%*400

=100

¡Espero que esto haya ayudado!

3 0
3 years ago
Pls help anyone us appreciated
MAVERICK [17]

x=angle CDB  (vertical angles)

=angle ABE (corresponding angles, AB parallel to CD)

=132-90   (exterior angle 132=sum of angles ABE and AEB)

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3 years ago
A sample of 26 offshore oil workers took part in a simulated escape exercise, and their escape time (unit: second) were observed
Anuta_ua [19.1K]

Answer:

t=\frac{370.69-360}{\frac{24.36}{\sqrt{26}}}=2.238  

The degrees of freedom are given by:

df = n-1= 26-1=25

And the p value would be:

p_v =P(t_{25}>2.238)=0.0172  

If we use a 5% of significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 360 second or 6 minutes. We need to be careful since if we use a significance level of 1% the result change

Step-by-step explanation:

Information given

\bar X=370.69 represent the sample mean

s=24.36 represent the sample standard deviation

n=26 sample size  

\mu_o =6*60 =360 s represent the value to verify

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to check if the true mean is at most 360 seconds, the system of hypothesis would be:  

Null hypothesis:\mu \leq 360  

Alternative hypothesis:\mu > 360  

The statistic for this case would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

We can replace in formula (1) the info given like this:  

t=\frac{370.69-360}{\frac{24.36}{\sqrt{26}}}=2.238  

The degrees of freedom are given by:

df = n-1= 26-1=25

And the p value would be:

p_v =P(t_{25}>2.238)=0.0172  

If we use a 5% of significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 360 second or 6 minutes. We need to be careful since if we use a significance level of 1% the result change

4 0
3 years ago
You are a landscaper and need to mulch 15 yards of plant beds. You have 20 bags of mulch and each bag covers 3 feet.
Umnica [9.8K]
Whats the question?

You'll need 15 bags to cover 15 yards
1 bag/ 3 feet
3 feet/ 1 yard

15 bags = 45 feet = 15 yards
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