By graph of object A the rate of change is estimated at 17/6.
Object B's rate of change is 10/3=20/6.
Comparing object A to object B:
17/6 <20/6
Object B is faster by:
17/6x=20/6
(6/17)(17/6)x=(20/6)(6/17)
x=20/17≈1.18
B)
Object B by a factor of 1.19
Since I made an estimation from graph of object A , my solution is off by. 01 but it is the closest I can get. The solution B is correct.
Answer:
The width of the garden is 100 feet.
Step-by-step explanation:
The formula for the perimeter of a rectangle is 2(L+W) where L = length and W = width.
Since we know the perimeter (the fence that surrounds the garden) is 820 feet and the length of the pen is 10 feet longer than 3 times its width, we can set an equation and solve for the width:
L = 10 + 3W
So substitute 10 + 3W for L in the equation:
2[(10 + 3W) + W) = 820
2(10 + 4W) = 820
10 + 4W = 410
4W = 400
W = 100
Therefore, the width of the garden is 100 feet.
Answer:
130.826 kilojoules
Step-by-step explanation:
The Work required to pump water = pgV
Where, p = density of water = 1000 kg/m³
g = acceleration due to gravity = 9.81ms-¹
V = volume of water
Since, radius r = 5 ft and height h = 9ft
Volume of water in the cylindrical tank = (2/3)πr²h
V = (2/3)π *5²*9 = 471.24 ft³ = 471.24 * 0.0283m³ = 13.336m³
Work required = 1000*9.81*13.336
W = 130.826 KJ
Therefore, the work required to pump water 2/3 of the volume of the cylindrical tank = 130.826 kilojoules.
<span>C. The surface area stays the same, but the number representing the surface area decreases.
1 yard = 3 ft, so the number in ft is greater. </span>
