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3 years ago

9

Peter bought 8 lemons for $6 What was the cost for 1 lemon?

2 answers:

saul85 [17]3 years ago

6 0

Answer: The cost for 1 lemon is $0.75.

Solution

Peter bought 8 lemons for $6. What was the cost for 1 lemon?

We can use a rule of three to solve this problem:

If 8 lemons cost $6

1 lemon cost x

x=(1 lemon)($6) / (8 lemon)

x=$(6/8)

x=$0.75

Alexeev081 [22]3 years ago

3 0

$1.3 per lemon. I divided 8 by $6 and got 1.3.

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Find the optimal solution for the following problem. (Round your answers to 3 decimal places.)

irina1246 [14]

Answer:

Maximize C = $9x + 7y$

$8x + 10y \leq 17$

$11x + 12y\leq 25$

and x ≥ 0, y ≥ 0

Plot the lines on graph

$8x + 10y \leq 17$

$11x + 12y\leq 25$

$x\geq 0$

$y\geq 0$

So, boundary points of feasible region are (0,1.7) , (2.125,0) and (0,0)

Substitute the points in Maximize C

At (0,1.7)

Maximize C = $9(0) + 7(1.7)$

Maximize C = $11.9$

At (2.125,0)

Maximize C = $9(2.125) + 7(0)$

Maximize C = $19.125$

At (0,0)

Maximize C = $9(0) + 7(0)$

Maximize C = $0$

So, Maximum value is attained at (2.125,0)

So, the optimal value of x is 2.125

The optimal value of y is 0

The maximum value of the objective function is 19.125

4 0

3 years ago

PROVE :<br><br>sin^2(-300°).cos^2 (120)+ cos^2(-240 ).sin^2(390)=1/4

leva [86]

Step-by-step explanation:

$\sin {}^{2} ( - 300) \cos {}^{2} (120) + \cos {}^{2} ( - 240) \sin {}^{2} (390) = \frac{1}{4}$

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$\frac{3}{4} \frac{1}{4} + \frac{1}{4} \frac{1}{4}$

$\frac{3}{16} + \frac{1}{16} = \frac{4}{16} = \frac{1}{4}$

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2 years ago

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nekit [7.7K]

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zimovet [89]

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pentagon [3]

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Wow that was long and hard to explain LOL. :)

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