All categories

3 years ago

HEY LOL PLEASE ANSWER THESE. PLEASE IM BEGGING YOU. HELP ME

Mathematics

1 answer:

Alexandra [31]3 years ago

5 0

Answer:

a. ∆ABC ~ ∆A'B'C'

b. Enlargement

c. Scale factor = 4

Step-by-step explanation:

a. <A corresponds to <A'

<B corresponds to <B'

<C corresponds to <C',

Therefore, the similarity statement would be: ∆ABC ~ ∆A'B'C'

b. The image of the dilation is an enlargement of the original figure because the side lengths of ∆A'B'C are larger than the corresponding side lengths of ∆ABC.

c. Scale factor = the ratio of the corresponding sides

Thus:

Scale factor = A'B'/AB = B'C'/BC = A'C'/AC

Scale factor = 24/6 = 48/12 = 60/15 = 4

Scale factor = 4

You might be interested in

3c-d=T Could you solve for c

RSB [31]

- - Let's solve for C.

Starting off with our equation:
$3c+d=T$

Transform:
$3c=T+D$

Solve for that:
$\frac{3c}{3} = \frac{T+D}{3}$

Solve for that for the last time and your answer is $\frac{T+D}{3} =C$

7 0

2 years ago

Read 2 more answers

1 (15 Points]. Prove the following statement: is divisible by 3 if only if it is a sum of three consecutive integers. be ddvisbk

Alinara [238K]

Answer:

First. Let us prove that the sum of three consecutive integers is divisible by 3.

Three consecutive integers can be written as k, k+1, k+2. Then, if we denote their sum as n:

n = k+(k+1)+(k+2) = 3k+3 = 3(k+1).

So, n can be written as 3 times another integer, thus n is divisible by 3.

Second. Let us prove that any number divisible by 3 can be written as the sum of three consecutive integers.

Assume that n is divisible by 3. The above proof suggest that we write it as

n=3(k+1)=3k+3=k + k + k +1+2 = k + (k+1) + (k+2).

As k, k+1, k+2 are three consecutive integers, we have completed our goal.

Step-by-step explanation:

4 0

2 years ago

A rectangular Corn Hole area at the Recreation Center has a width of 5 feet and a length of 10 feet. If

lbvjy [14]

Answer:

2ft

Step-by-step explanation:

5 x 10=50

7 x 12= 84

5+2=7 and 10+2=12

3 0

3 years ago

3 ½ x 2/5 *

ki77a [65]

Answer:

Step-by-step explanation:

$3\frac{1}{2}=\frac{(3*2)+1}{2}=\frac{7}{2}\\\\\\3\frac{1}{2}*\frac{2}{5}=\frac{7}{2}*\frac{2}{5}=\frac{14}{10}$

4 0

2 years ago

To rationalize the denominator of 2/square 13+ squared 11 , you should multiply the expression by which fraction?

eimsori [14]

Answer:

You should multiply the expression by $\frac{\sqrt{13}-\sqrt{11}}{\sqrt{13}-\sqrt{11}}$

Explanation:

To rationalize any expression, you must multiply it by its conjugate. A conjugate is defined as a similar expression to the original one but with an opposite sign

This means that:

The conjugate of a + b would be a - b

Now, the given expression is $\frac{2}{\sqrt{13}+\sqrt{11}}$

Consider the denominator:

From the above, we can conclude that the conjugate of $\sqrt{13}+\sqrt{11}$ is $\sqrt{13}-\sqrt{11}$

And, remember that we need to keep the value of the expression unchanged. This means that we must multiply both the numerator and the denominator by the same value

Therefore:

You should multiply the expression by $\frac{\sqrt{13}-\sqrt{11}}{\sqrt{13}-\sqrt{11}}$ in order to rationalize the denominator

Hope this helps :)

5 0

3 years ago

Read 2 more answers