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3 years ago

A circumscribed figure is inside another figure while an inscribed figure is outside another. True or false

1 answer:

4 0

The term circumscribed means to limit, to restrain, or to surround. The figure circumscribed another figure means it is outside of that figure. On the other hand, the term inscribed means to draw the figure within another. This means that it should be inside another figure.

The given descriptions above are the exact opposite of the true meaning. Hence, the answer to this item is FALSE.

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I really need this answer ASAP! Please answer correctly! No links please.

Mademuasel [1]

Answer:

Step-by-step explanation:

Slope= - 6/7

Point (-4, 2)

b = y - (m)(x)

b = 2- (-6/7)(-4)

b = 2 - 24/7

b = -10/7

y = - 6/7x - 10/7

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3 years ago

Calculate the angle between the longest side and the diagonal of a 577mm by 1000mm rectangle

krok68 [10]

This should help in the photo

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3 years ago

How do you do slopes in Math I wanna learn To know The applied Math so I can pass My ged

IgorLugansk [536]

Answer:

The slope will be the same for a straight line no matter which two points you pick as you know. All you need to do is to calculate the difference in the y coordinates of the 2 points and divide that by the difference of the x coordinates of the points(rise over run). That will give you the slope.

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3 years ago

Factor the trinomial 3x^2+12x+9

blondinia [14]

Answer:

x^2 + 4x + 3

Step-by-step explanation:

divide everything by 3

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3 years ago

Two search teams spot a stranded climber on a mountain. The first search team is 0.5 miles from the second search team. If the a

shepuryov [24]

Answer:

The altitude of the climber is 1.40 miles

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

In the right triangle BCD

tan(22°)=h/(x-0.5)

h=tan(22°)*(x-0.5) ----> equation A

In the right triangle ACD

tan(15°)=h/x

h=tan(15°)*(x) ----> equation B

Equate equation A and equation B and solve for x

tan(22°)*(x-0.5)=tan(15°)*(x)

tan(22°)*x-tan(22°)*0.5=tan(15°)*x

x[tan(22°)-tan(15°)]=tan(22°)*0.5

x=tan(22°)*0.5/[tan(22°)-tan(15°)]

x=1.48 miles

Find the value oh h

h=tan(15°)*(1.48)=0.40 miles

therefore

The altitude of the climber is equal to

0.40+1=1.40 miles

6 0

4 years ago