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4 years ago

15) -1 - 2mx =6yx solve for x

Mathematics

1 answer:

tekilochka [14]4 years ago

8 0

Answer : - 1 / 6y + 2m
The full solution is in the photo:)
( sorry if it’s wrong ;-; )

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2 years ago

Consider the line - 4x – 3y = 5.

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The slope of the perpendicular line is 1/4

A line parallel to this will have the same gradient of -4.

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3 years ago

Solve. Check that your answer is reasonable. Paula's painting has a perimeter of 1.22 meters. She wants to put ribbon around the

iren2701 [21]

Answer:

5 pieces

Step-by-step explanation:

Given:

Paula's painting has a perimeter of 1.22 meters.

She wants to put ribbon around the edge.

If the ribbon comes in pieces that are 25 centimeters long.

Question asked:

How many pieces of ribbon does she need to go all the way around her painting?

Solution:

Perimeter of painting = 1.22 meters

First of all we will convert it into centimeters:-

As we know:

1 meter = 100 centimeters

1.22 meters = 100 $\times$ 1.22 = 122 centimeters

Now, as given that ribbon comes in pieces of 25 cm long and total we should have 122 cm to go all the way around the painting.

Number of pieces of ribbon will be needed = $\frac{122}{25} =4.88\$

Thus, she need 5 pieces of 25 cm long ribbon to go all the way around the painting.

<u>Note</u>:-This is by default understood that few length of 5th ribbon will be left over.

3 0

3 years ago

Two boats leave port at noon. Boat 1 sails due east at 12 knots. Boat 2 sails due south at 8 knots. At 2 pm the wind diminishes

Ivan

Answer:

14.86 knots.

Step-by-step explanation:

<em>Given that:</em>

The boats leave the port at noon.

Speed of boat 1 = 12 knots due east

Speed of boat 2 = 8 knots due south

At 2 pm:

Distance traveled by boat 1 = 24 units due east

Distance traveled by boat 2 = 16 units due south

Now, speed of boat 1 changes to 9 knots:

At 3 pm:

Distance traveled by boat 1 = 24 + 9= 33 units due east

Distance traveled by boat 2 = 16+8 = 24 units due south

Now, speed of boat 1 changes to 8+7 = 15 knots

At 5 pm:

Distance traveled by boat 1 = 33 + 2 $\times$ 9= 51 units due east

Distance traveled by boat 2 = 24 + 2 $\times$ 15 = 54 units due south

Now, the situation of distance traveled can be seen by the attached right angled $\triangle AOB$ .

O is the port and A is the location of boat 1

B is the location of boat 2.

Using pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^{2} = 51^{2} + 54^{2}\\\Rightarrow AB^{2} = 2601+ 2916 = 5517\\\Rightarrow AB = 74.28\ units$

so, the total distance between the two boats is 74.28 units.

Change in distance per hour = $\dfrac{Total\ distance}{Total\ time}$

$\Rightarrow \dfrac{74.28}{5} = 14.86\ knots$

6 0

3 years ago

Pls help i will put Brainliest

anzhelika [568]

Answer:

It would have to be cup C.

8 0

3 years ago

15) -1 - 2mx =6yx solve for x​

15) -1 - 2mx =6yx solve for x