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Mariulka [41]
3 years ago
13

13 cans of paint with 5/6 liters of paint in each were used to paint 4 identical cars. How can you calculate the amount of paint

used for each car? Select all that apply.
(A) 5/6 ·4÷13 (B) 5/6 ·13÷4 (C) 5/6 ÷4·13
(D) 5/6 · 13/4 (E) 5/6 ÷13·4 (F) 5/6 · 4/13
Mathematics
1 answer:
brilliants [131]3 years ago
3 0

Answer:

(B) 5/6 ·13÷4

(C) 5/6 ÷4·13

(D) 5/6 · 13/4

Step-by-step explanation:

Amount of paint per can = \[\frac{5}{6}\] liters.

Number of cans used to paint 4 cars = 13

Total amount of paint used for 4 cars = \[13 * \frac{5}{6}\] liters.

= \[\frac{13 * 5}{6}\] liters.

= \[\frac{65}{6}\] liters.

Total amount of paint used for 1 car = \[\frac{65}{6} \div 4\] liters.

= \[\frac{65}{24}\] liters.

Of the given options, option B,C and D correspond to the same value.

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Suppose that a recent article stated that the mean time spent in jail by a first-time convicted burglar is 2.5 years. A study wa
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Using the z-distribution, it is found that since the <u>test statistic is greater than the critical value</u>, it can be concluded that the mean length of jail time has increased.

At the null hypothesis, it is <u>tested if the mean length of jail time is still of 2.5 years</u>, that is:

H_0: \mu = 2.5

At the alternative hypothesis, it is <u>tested if it has increased</u>, that is:

H_1: \mu > 2.5

We have the <u>standard deviation for the population</u>, thus, the z-distribution is used. The test statistic is given by:

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For this problem, the values of the <u>parameters</u> are: \overline{x} = 3, \mu = 2.5, \sigma = 1.5, n = 26

Hence, the value of the <u>test statistic</u> is:

z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{3 - 2.5}{\frac{1.5}{\sqrt{26}}}

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A similar problem is given at brainly.com/question/24166849

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