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Ganezh [65]
3 years ago
9

True or false???????????

Mathematics
2 answers:
Sedbober [7]3 years ago
6 0
The answer is true because they are both positive numbers
AleksandrR [38]3 years ago
5 0
True.
no matter what value you put in x, it will produce positive real numbers.
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(2,0) (3,9) equation
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Step-by-step explanation:

That's what i was taught I'm in 8th grade tho so

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The table shows the amount of time, in minutes, it takes to walk a given distance, in miles, along the path. Complete the table
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Write them least to greatest...
rewona [7]
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3 0
3 years ago
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Paha777 [63]

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3 0
3 years ago
If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2<br> Express answer as a common fraction.<br> Thanks!!
timama [110]

x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0

By the quadratic formula,

x^2=\dfrac{3\pm\sqrt5}2\implies x^2+1=\dfrac{5\pm\sqrt5}2

Then

(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2

\implies\dfrac{x^2}{(x^2+1)^2}=\dfrac{\frac{3\pm\sqrt5}2}{\frac{15\pm5\sqrt5}2}=\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}

Multiply numerator and denominator by the denominator's conjugate:

\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15

3 0
3 years ago
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