Answer:
count me in
Step-by-step explanation:
Answer: x=10
Step-by-step explanation:
3x+2/24=12/9
9(3x+2)=288
27×+18=288
-18
27x=270/27
x=10
Given f(x) = x^2 + 1 and g(x) = x-2
a. Find (f-g)(-2)
[f-g](x) = f(x) - g(x) = x^2-x+3
[f-g](-2) = (-2)^2-(-2)+3 = 9
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b. Find f[g(5)]
f[g(5)] = f[5-2] = f[3] = 9+1 = 10
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problem a.
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(f-g)(x) = f(x) - g(x)
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(f-g)(-2) = f(-2) - g(-2)
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f(x) = x^2 + 1
f(-2) = (-2)^2 + 1
f(-2) = 4+1
f(-2) = 5
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g(x) = x-2
g(-2) = -2-2
g(-2) = -4
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f-g(-2) = f(-2) - g(-2) = 5 - (-4) = 5 + 4 = 9
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answer for a is:
f-g(-2) = 9
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problem b.
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g(x) = x-2
g(5) = 5-2
g(5) = 3
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f(x) = x^2 + 1
f(g(5)) = (g(5))^2 + 1
since g(5) = 3, equation becomes:
f(g(5)) = 3^2 + 1
f(g(5)) = 9 + 1 = 10
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answer for b is:
f(g(5)) = 10
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in general, you substitute whatever value is replacing x in the equation to get your answers.
looking at problem b in this way, we would get a general solution as follows:
f(x) = x^2 + 1
g(x) = x-2
substitute g(x) for x:
f(g(x)) = (g(x))^2 + 1
substitute the equation for g(x) on the right hand side.
f(g(x)) = (x-2)^2 + 1
remove parentheses:
f(g(x)) = x^2 - 4*x + 4 + 1
simplify:
f(g(x)) = x^2 - 4*x + 5
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substituting 5 for x:
f(g(5)) = (5^2 - 4*5 + 5
simplifying:
f(g(5)) = 25 - 20 + 5
f(g(5)) = 10
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answer is the same as above where we first solved for g(5) which became 3, and then substituted that value in f(g(x)) which made it f(3)).
Hope this helps!
Answer:
Add the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for the remaining variables.
Point Form:(1,1)
Step-by-step explanation:
First in factoring, you must find out what is common in the whole equation
Now, make 2 sets of parentheses and "split up" the rest of the equation
Try to experiment which numbers work out
We are not subtracting anything so both parentheses are positive
Therefore, the factored version of
is
