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2 years ago

List the first 5 multiples of, find all the factors of 7

2 answers:

8 0

What # do you need the first five multiples for? and the only factors for 7 are one and seven because it is a prime number!

Anna007 [38]2 years ago

6 0

Factors of 7 are 1 and 7 and that's it because it is prime number and the 5 multiples are
1,2,3,4,5
2,4,6,8,10
3,6,9,12,15
4,8,12,16,20
5,10,15,20,25
6,12,18,24,30
7,14,21,28,35
8,16,24,32,40
9,18,27,36,45
10,20,30,40,50

Hope that helped

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<img src="https://tex.z-dn.net/?f=-2%5Csqrt%7B18%7D%20%2B2%5Csqrt%7B2%7D" id="TexFormula1" title="-2\sqrt{18} +2\sqrt{2}" alt="-

UkoKoshka [18]

Answer:

- 4 $\sqrt{2}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Simplify $\sqrt{18}$ using this rule

$\sqrt{18}$

= $\sqrt{9(2)}$

= $\sqrt{9}$ × $\sqrt{2}$ = 3 $\sqrt{2}$

Then

- 2 $\sqrt{18}$ + 2 $\sqrt{2}$

= - 2(3 $\sqrt{2}$ ) + 2 $\sqrt{2}$

= - 6 $\sqrt{2}$ + 2 $\sqrt{2}$

= - 4 $\sqrt{2}$

5 0

2 years ago

A special liquid is held in a tank described as (x 2 + y 2 ) ≤ z ≤ 1 in a Cartesian coordinate system. Assume that the density o

vivado [14]

Since $\rho=\dfrac mV$ (density = mass/volume), we can get the mass/weight of the liquid by integrating the density $\rho(x,y,z)$ over the interior of the tank. This is done with the integral

$\displaystyle\int_{-1}^1\int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}}\int_{x^2+y^2}^1(2-z^2)\,\mathrm dz\,\mathrm dy\,\mathrm dx$

which is more readily computed in cylindrical coordinates as

$\displaystyle\int_0^{2\pi}\int_0^1\int_{r^2}^1(2-z^2)r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\boxed{\frac{3\pi}4}$

7 0

2 years ago

Which of the following is a linear function?

irga5000 [103]

Answer: C

Step-by-step explanation:^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

5 0

2 years ago

Read 2 more answers

Year 9 Maths - linear equations please help

jek_recluse [69]

Answer:

x=1 & y=6 or (1,6)

Step-by-step explanation:

3x-x+5=7 Substitute the 2nd equation in for y

2x+5=7 Do 3x-x to get 2x

2x=2 Subtract 5 from both sides

x=1 Divide 2 from both sides

y=1+5 Insert 1 as x

y=6 Add 1+5 to solve for y

Hope this helped!

3 0

3 years ago

Read 2 more answers

What are the roots of the equation? x^2+24=−11x Enter your answers in the boxes.

docker41 [41]

The correct answers are:

x=-3 and x=-8.

Explanation:

We can first write this in standard form, ax²+bx+c=0. To do this, we will add 11x to both sides:
x²+24+11x=-11x+11x
x²+11x+24=0.

Now we can factor this. Look for factors of c, 24, that sum to b, 11. Factors of 24 are:
1 and 24 (sum 25)
2 and 12 (sum 14)
3 and 8 (sum 11)
4 and 6 (sum 10).

The factors we need are 3 and 8, since they sum to 11. This gives us factored form:
(x+3)(x+8)=0.

Using the zero product property, we know that in order to have a product of 0, one or both of the factors must be 0. This means we have:
x+3=0 or x+8=0.

Solving the first equation:
x+3-3=0-3
x=-3.

Solving the second equation:
x+8-8=0-8
x=-8.

8 0

2 years ago

Read 2 more answers