Answer:
52
Step-by-step explanation:
A cubical box without a top is 4 cm on each edge containing 64 identical 1 cm cubes.
We have to find the number of small cubes that actually touch the box.
Now, there are 4 layers of 16 cubes from bottom to top.
In the bottom-most layer, all the 16 small cubes will touch the bottom of the large cube.
Again, from the top three layers, only the outer small cubes will touch the sides of the large cube.
So, there are 12 small cubes in each top three layers that will touch the large cube.
Hence, in total there will be (16 + 12 ×3) = 52 small cubes that actually touch the large cube box. (Answer)
we are given
trinomial as
now, we can factor it
so, option-C and D ..............Answer
Answer:
0.0918
Step-by-step explanation:
We know that the average amount of money spent on entertainment is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The mean and standard deviation of average spending of sample size 25 are
μxbar=μ=95.25
σxbar=σ/√n=27.32/√25=27.32/5=5.464.
So, the average spending of a sample of 25 randomly-selected professors is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The z-score associated with average spending $102.5
Z=[Xbar-μxbar]/σxbar
Z=[102.5-95.25]/5.464
Z=7.25/5.464
Z=1.3269=1.33
We have to find P(Xbar>102.5).
P(Xbar>102.5)=P(Z>1.33)
P(Xbar>102.5)=P(0<Z<∞)-P(0<Z<1.33)
P(Xbar>102.5)=0.5-0.4082
P(Xbar>102.5)=0.0918.
Thus, the probability that the average spending of a sample of 25 randomly-selected professors will exceed $102.5 is 0.0918.
Answer:
see image about. I think that is what you are looking for
It would take 6 weeks for Cole to make 750$ and the 65$ he had received from the open mic would make it 815$
