Let two number A and B, and A >B
as we know A+10=2B① && A+B =38②
①-② solve that
B=16 so A=22
so, they are 16 and 22
<span>Part
A: Solve A = (x + 23) for x.
A = x + 23
=> A - 23 = x + 23 - 23
=> A - 23 = x
=> x = A - 23 <------- answer
Part B: Determine the value of x
when A = 108
Replace the value of A in the expression x = A - 23
x = 108 - 23 = 75
x = 75 <------- answer
Part C: Solve -np - 90 > 30 for n.
-np - 90 > 30
=> -np + np - 90 >30 + np
=> - 90 > 30 + np
=> -90 - 30 > 30 - 30 + np
=> -120 > np
=> np < - 120 <----- answer
</span>
Answer:
f(x) = 2x3 + 4
Stretch vertically be a factor of 2:
f(x) = 2*2x3 + 4 = 4x3 + 4
Shift 5 units to the left:
f(x) = 4(x+5)3 + 4
7 1/5 - 2 3/5 =
36/5 - 13/5 =
23/5 or 4 3/5 <==
Answer:
Therefore,
Step-by-step explanation:
Given:
Let,
point L( x₁ , y₁) ≡ ( -6 , 2)
point M( x₂ , y₂ )≡ (x , 2)
l(AB) = 15 units (distance between points L and M)
To Find:
x = ?
Solution:
Distance formula between Two points is given as
Substituting the values we get
Square Rooting we get
As point M is located in the first quadrant
x coordinate and y coordinate are positive
So x = -21 DISCARDED
Hence,
Therefore,
