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Hunter-Best [27]
3 years ago
11

The number of new cars purchased in a city can be modeled by the equation C=20t to the 2nd power, where C is the number of new c

ars and t = 0 corresponds to the number of new cars purchased in 1998. In what yr. will the number of new cars purchased reach 15,000?​
Mathematics
1 answer:
Allisa [31]3 years ago
4 0

Answer:

1998 + 5\sqrt{30}

Step-by-step explanation:

Set up the equation:

Since C(t) gives the number of cars purchased in the t-th year after 1998, then make the number of cars equal to 15 000 and solve for t - the year:

20t^2 = 15000

t^2 = 750

t = \sqrt{750} = \sqrt{10} \cdot \sqrt{25} \cdot \sqrt{3} = 5\sqrt{30}

The year will be simply 1998 + 5 \sqrt{30}

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Click on the picture thanks so much
-BARSIC- [3]

Answer:

$3.06

Step-by-step explanation:

First we need to calculate the mark up

The mark-up rate is 150% = 1.5 as a decimal

New price = original price + original price * markup rate

                 = 61.20 + 61.20* 1.50

                 = 61.20 + 91.80

                = 153

The new price is 153.00

Commission is the price times his commission rate

commission = price* .02

                    = 153*.02

                     = 3.06

Neil will make 3.06 on the sale of the table

7 0
3 years ago
Mark and Hayden won a raffle and decide to split the money using the ratio 9:8. If Hayden received $64, which of the following w
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I believe the answer is $72
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3 years ago
............................
prohojiy [21]
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After flipping positions/eliminating the negative exponents it should look like this:

\frac{ 2^{2} x^{3} }{ y^{5} }
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\frac{4 (2)^{3} }{ (-4)^{5} }
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Final Answer: - \frac{1}{32} [/tex]
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2 years ago
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