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Hunter-Best [27]
3 years ago
11

The number of new cars purchased in a city can be modeled by the equation C=20t to the 2nd power, where C is the number of new c

ars and t = 0 corresponds to the number of new cars purchased in 1998. In what yr. will the number of new cars purchased reach 15,000?​
Mathematics
1 answer:
Allisa [31]3 years ago
4 0

Answer:

1998 + 5\sqrt{30}

Step-by-step explanation:

Set up the equation:

Since C(t) gives the number of cars purchased in the t-th year after 1998, then make the number of cars equal to 15 000 and solve for t - the year:

20t^2 = 15000

t^2 = 750

t = \sqrt{750} = \sqrt{10} \cdot \sqrt{25} \cdot \sqrt{3} = 5\sqrt{30}

The year will be simply 1998 + 5 \sqrt{30}

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3 years ago
The manufacturer of a weight-training bench spends $15 to build each bench and sells them for $32. The manufacturer also has fix
nasty-shy [4]

Answer:

Step-by-step explanation:

C(x) = 15x + 25,500....cost function

R(x) = 32x .....revenue function

break even point (when they are equal)....so set them equal and solve for x

15x + 25,500 = 32x

25,500 = 32x - 15x

25,500 = 17x

25,500 / 17 = x

1500 = x.......so the break even point is when 1500 benches are sold

15x + 25,500 =                                   32x =

15(1500) + 25,500                              32(1500) =

22,500 + 25,500                                48,000

48,000

and after selling 1500 benches, they will both equal $48,000

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