So I'm assuming that you're taking Calculus.
The first thing you want to do is take the integral of f(x)...
Use the power rule to get:
4X^2-13X+3.
Now solve for X when f(x)=0. This is because when the slope is 0, it is either a minimum or a maximum(I'm assuming you know this)
Now you get X=0.25 and X=3. Since we are working in the interval of (1,4), we can ignore 0.25
Thus our potential X values for max and min are X=1,X=4,X=3(You don't want to forget the ends of the bounds!)
Plugging these value in for f(x), we get
f(1)=2.833
f(3)=-8.5
f(4)=1.667
Thus X=1 is the max and X=3 is the min.
So max:(1,2.833)
min:(3,-8.5)
Hope this helps!
J.
x represents the minutes and y shows how many gallons over that time.
Answer:
9 units
Step-by-step explanation:
Calculate the absolute value of the difference, that is
| - 2 - 7 | = | - 9 | = 9 , or
| 7 - (- 2) | = | 9 | = 9
-2(-2)^4 + 5(-2)^2 - 4
-2(-2)= 4. 4^4= 16
5(-2)= -10. -10^2= 100 - 4= 96
96 + 16= 112
Answer: 112
