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Setler79 [48]
3 years ago
7

What is a multiple of 7 and is also a factor of 7

Mathematics
1 answer:
olga2289 [7]3 years ago
4 0
28 is a multiple of 7 and also a factor of seven!
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Medication errors can constitute malpractice and can include a) failure to treat in a timely manner. O b) prescribing medication
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Answer:

a) failure to treat in a timely manner

Step-by-step explanation:

Failure to treat in a timely manner is considered malpractice because it is considered negligence and can result in the worsening of the condition.

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Find 85% of the number 33.51 help
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33.51 X 85% (0.85) = 28.48
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Additive inverse of −2, additive identity of −5, additive inverse of 3, multiplicative identity of 19, and multiplicative invers
monitta

Answer:

See Explanation

Step-by-step explanation:

a) Additive inverse of −2

  • the additive inverse of a number a is the number that, when added to 'a', yields zero. This number is also known as the opposite (number), sign change, and negation.
  • So the Additive inverse of -2 is 2. ∴ -2+2=0

b) Additive identity of −5

  • Additive identity is the value when added to a number, results in the original number. When we add 0 to any real number, we get the same real number.
  • -5 + 0 = -5. Therefore, 0 is the additive identity of any real number.

c) additive inverse of 3

  • Two numbers are additive inverses if they add to give a sum of zero. 3 and -3 are additive inverses since 3 + (-3) = 0. -3 is the additive inverse of 3.

d). multiplicative identity of 19

  • an identity element (such as 1 in the group of rational numbers without 0) that in a given mathematical system leaves unchanged any element by which it is multiplied
  • Multiplicative identity if 19 is 1 only, since 19 x 1 = 19.

e) multiplicative inverse of 7

  • Dividing by a number is equivalent to multiplying by the reciprocal of the number. Thus, 7 ÷7=7 × 1⁄7 =1. Here, 1⁄7 is called the multiplicative inverse of 7.

d)  | 11-5|×|1-5|

  • | 11-5|×|1-5| ⇒ I6I×I-4I ⇒ 6×4 ⇒ 24

8 0
3 years ago
A circle is centered at (11, −9) and has a radius of 12.
ahrayia [7]
\bf \textit{equation of a circle}\\\\
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllcl}
center\quad  (&h,&\quad  k)\qquad
radius=&r\\
&11&-9&12
\end{array}
6 0
3 years ago
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