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2 years ago

Another object has a density of 18 kg/m3 and a mass of 360kg what is the volume of the object

Mathematics

1 answer:

Nikitich [7]2 years ago

8 0

Answer:

Length(L)=18kg

=18×100cm=1800

Breadth(B)=360kg

Height(H)=m3

Volume (V)=?

We know,

V=l×b×h

or, V=18×360×m3

=6480

Step-by-step explanation:

I think it is useful

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Rich is tossing a normal quarter. He tosses the quarter 25 times and it lands on heads 5 times. If Rich tosses the quarter again

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YOOO PLEASE HELPPPP!!!!

Evgesh-ka [11]

Given:

Base length of triangle = 40 units

Height of triangle = 9 units

Length of hypotenuse of triangle = 41 units

To find:

Find the value of Tan A

Steps:

Tan of an angle is equal to the opposite length by adjacent length.

So,

Tan A = $\frac{opposite}{adjacent}$

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Tan A = 0.225

Therefore, the exact value of Tan A is 0.225.

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4 0

3 years ago

Given f(x)=4x+5 and g(x)= x^2+x; find (f∘g)(-5) Please show all steps thank you

Greeley [361]

Answer:

$(f\circ g)(-5)=85$

Step-by-step explanation:

We are given:

$\displaystyle f(x)=4x+5\text{ and } g(x)=x^2+x$

And we want to find:

$(f\circ g)(-5)$

This is equivalent to:

$\displaystyle =f(g(-5))$

So, we will evaluate g(-5) first, which yields:

$\displaystyle g(-5)=(-5)^2+(-5)=25-5=20$

So:

$=f(g(-5))=f(20)$

Then:

$\displaystyle f(20)=4(20)+5=80+5=85$

Therefore:

$(f\circ g)(-5)=85$

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3 years ago