How do you know if two lines are parallel given coordinates only? How do you know if two lines are perpendicular given coordinat
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Now, there are 360° in a circle, how many times does 360° go into 1860°?
well, let's check that,
now, this is a negative angle, so it's going clockwise, like a clock moves, so it goes around the circle clockwise 5 times fully, and then it goes 1/6 extra.
well, we know 360° is in a circle, how many degrees in 1/6 of 360°? well, is just 360/6 or their product, and that's just 60°.
so -1860, is an angle that goes clockwise, negative, 5 times fully, then goes an extra 60° passed.
5 times fully will land you back at the 0 location, if you move further down 60° clockwise, that'll land you on the IV quadrant, with an angle of -60°.
therefore, the csc(-1860°) is the same as the angle of csc(-60°), which is the same as the csc(360° - 60°) or csc(300°).
well, let's check that,
now, this is a negative angle, so it's going clockwise, like a clock moves, so it goes around the circle clockwise 5 times fully, and then it goes 1/6 extra.
well, we know 360° is in a circle, how many degrees in 1/6 of 360°? well, is just 360/6 or their product, and that's just 60°.
so -1860, is an angle that goes clockwise, negative, 5 times fully, then goes an extra 60° passed.
5 times fully will land you back at the 0 location, if you move further down 60° clockwise, that'll land you on the IV quadrant, with an angle of -60°.
therefore, the csc(-1860°) is the same as the angle of csc(-60°), which is the same as the csc(360° - 60°) or csc(300°).
In short, (h o g)(a) is just h( g(a) ).
so what we can do is simply get g(a) first and then plug that in h(x).
so what we can do is simply get g(a) first and then plug that in h(x).