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tatuchka [14]
4 years ago
6

Find x in the following diagram

Mathematics
1 answer:
andreyandreev [35.5K]4 years ago
8 0

Answer:

x = 71

Step-by-step explanation:

The sum of the measures of the exterior angles of a polygon is always 360°.

A triangle has 3 exterior angles.

152+ 137+x = 360

Combine like terms

289 +x = 360

Subtract 289 from each side

289-289+x=360-289

x = 71

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Please solve the one step equation x/5-11=10
Nostrana [21]
when solving one step equations like this one etcetera this is how you get this answer 105 divided by 5 -11 equals 10
3 0
4 years ago
List the partial products of 42 x 28
tester [92]

Solution: The partial products of 42\times28 are 800, 320, 40, 16 and the value of 42\times28 is 1176.

Explanation:

To find the partial product of two numbers, first we write the both numbers as the sum of place values of the digits. Multiply each the place value of first number with the place value of second number.

42\times28

(40+2)\times(20+8)

40\times 20+40\times 8+2\times 20+2\times 8

Multiply each pair individually.

40\times 20=800

40\times 8=320

2\times 20=40

2\times 8=16

The above values are partial product.

800+320+40+16=1176

Therefore, the partial products of 42\times28 are 800, 320, 40, 16 and the value of 42\times28 is 1176.

7 0
3 years ago
Read 2 more answers
PLLLLZZZZZZZZZZZZZZ HELPPPP ASAP 10 POINTS! <br> AND PLZ do both if u can!! &lt;3 :(
frutty [35]

Answer:

13p and 4p+3

Step-by-step explanation:

Add similar elements: 12p+p=13p

Add/Subtract the numbers: 6-3=3

6 0
3 years ago
You are dealt one card from a 52-card deck. Find the probability that you are dealt: a numbered card or a heart
Alexandra [31]
One outta 52 is the probability
7 0
3 years ago
What is the distance between points (8,3) and (8,-6) on a coordinate plane?
Irina-Kira [14]

To calculate the distance between two points, we can use a formula that is a variation Pythagorean Theorem. Look:


\mathsf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}


"d" represents the distance and coordinates are expressed as follows: (x, y)


Let's go to the calculations.


\mathsf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}\\\\ \mathsf{d=\sqrt{(8-8)^2+(-6-3)^2}}\\\\ \mathsf{d=\sqrt{(0)^2+(-9)^2}}\\\\ \mathsf{d=\sqrt{0+81}}\\\\ \mathsf{d=\sqrt{81}}\\\\ \underline{\mathsf{d=9}}


The answer is 9 u.c.

3 0
3 years ago
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