Question

What is the product? StartFraction x squared minus 16 Over 2 x + 8 EndFraction times StartFraction x cubed minus 2 x squared + x Over x squared + 3 x minus 4 EndFraction

Answer 1

Answer:

[x(x - 1)(x - 4)]/(2(x + 4))

Step-by-step explanation:

We want to find;

[(x² - 16)/(2x + 8)] * [(x³ - 2x² + x)/(x² + 3x - 4)]

Now,

x² - 16 can be factorized as;

(x + 4)(x - 4)

Also, 2x + 8 can be factorized as;

2(x + 4)

Also, (x³ - 2x² + x) can factorized as;

x[x² - 2x + 1] = x[(x - 1)(x - 1)]

Also,(x² + 3x - 4) can be factorized out as; (x - 1)(x + 4)

So plugging in these factorized forms into the equation in the question, we have;

[(x + 4)(x - 4)/(2(x + 4))] * [x[(x - 1)(x - 1)] /((x - 1)(x + 4))

This gives;

((x - 4)/2) * x(x - 1)/(x +4)

This gives;

[x(x - 1)(x - 4)]/(2(x + 4))

Answer 2

Answer:

[x(x - 1)(x - 4)]/(2(x + 4))

Step-by-step explanation:

its A on edg

StartFraction x (x minus 4) (x minus 1) Over 2 (x + 4) EndFraction