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maks197457 [2]
4 years ago
7

Help please! Whoever gives the most explanation will receive: Brainliest Answer, 5 Stars, and a Thank you.

Mathematics
1 answer:
Dmitriy789 [7]4 years ago
6 0
Where is the grid? I need to see the grid to answer the question
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Help me with the question in the pic please and thank u!
Zepler [3.9K]

Answer:

1.98

Step-by-step explanation:

In this problem, we are:

Given: ∠D = 26°, Hypotenuse (DF) = 4.5

To solve: EF

Now through the given, we are to focus on point D to solve for EF.

We need to find the relationship of point D to DF and EF.

The relationship here is sine.

Reason: \frac{opposite}{hypotenuse}

Through point D, DF is the hypotenuse and EF is the opposite side.

So let's solve this simply through algebra,

sin = \frac{opposite}{hypotenuse}

sin(26°) = \frac{EF}{4.5}

0.44 = \frac{EF}{4.5}

0.44 × 4.5 = EF

1.98 = EF

7 0
4 years ago
someone please help me
Fynjy0 [20]
The answer is false, because if you do rise/run. You're rising 2 and running 1 so that's 2/1 which equals to 2, which is not between 0 and 1 !
3 0
3 years ago
Does anyone know the answer??
BigorU [14]

Answer:

x = -1 or x = 7

is the required solution of 4|x - 3| - 8 = 8

Step-by-step explanation:

Given:

4|x - 3| - 8 = 8

To Find:

x = ?

Solution:

We have

4|x - 3| - 8 = 8

∴ \therefore 4|x - 3| - 8 = 8\\\therefore 4|x - 3| = 8 + 8\\\therefore |x - 3| =\frac{16}{4}\\ \therefore |x - 3| =4

As there is Modulus sign MOD has two values i.e one with positive value and other with negative value.

∴ (x-3) =4\ or\ (x-3)=-4\\\therefore x =4+3\ or\ x=3-4 \\\therefore x =7\ or\ x =-1

x = -1 or x = 7

is the required solution of 4|x - 3| - 8 = 8

4 0
3 years ago
Loren drove 200 miles at a certain rate, and his wife, Lois, drove 100 miles at a rate 10 mph slower. If Loren had driven for th
NeX [460]

As long as Loren drove, the law of motion was

200 = st_1 \implies t_1 = \dfrac{200}{s}

As long as Loid drove, the law of motion was

100 = (s-10)t_2 \implies t_2 = \dfrac{100}{s-10}

So, the total time they took is

t_1+t_2=\dfrac{200}{s}+\dfrac{100}{s-10}

Had Loren driven the whole time, the law of motion would have been

300=st_3 \implies t_3 = \dfrac{300}{s}

And we know that this time would have been 30 minutes (i.e. 0.5 hours) faster. So, we have

t_3 = t_1+t_2-0.5

This translates into

\dfrac{300}{s}=\dfrac{200}{s}+\dfrac{100}{s-10}-\dfrac{1}{2}

If we subtract 200/s from both sides, we have

\dfrac{100}{s}=\dfrac{100}{s-10}-\dfrac{1}{2}

We can simplify the right hand side by summing the two fractions:

\dfrac{100}{s-10}-\dfrac{1}{2} = \dfrac{200-(s-10)}{2(s-10)}=\dfrac{210-s}{2(s-10)}

So, we have to solve

\dfrac{100}{s}=\dfrac{210-s}{2(s-10)}

If we cross multiply the denominators, we have

200(s-10)=s(210-s) \iff 200s-2000=210s-s^2 \iff s^2-10s-2000=0

Which yields the solutions

s=-40,\quad s=50

We accept the positive solution, because the negative would mean to travel backwards, so Loren's rate was 50mph

5 0
3 years ago
Read 2 more answers
Why is a variable exponent a number plus a variable adds eg: (x)*+(x) =?<br>​
oksano4ka [1.4K]

Answer:

10+10=20

debes  omer bien putasc

3 0
4 years ago
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