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maks197457 [2]
3 years ago
7

Help please! Whoever gives the most explanation will receive: Brainliest Answer, 5 Stars, and a Thank you.

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
6 0
Where is the grid? I need to see the grid to answer the question
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Danes puppy weighd 8oz at birth .The pup weighs 18 times more. So what is his weight now.
katrin [286]
You multiply 18 by 8 and you get 144
so the puppys weight is 144oz now
5 0
3 years ago
Find the values of x work 10% of my grade
Ostrovityanka [42]

Answer:

x = 35

Step-by-step explanation:

1. Add all angles

115+(x+36)+24+(2x+10)+2x

= 5x+185

2. Match 360 and fix

5x+185=360

5x=360-185

5x=175

x=175/5

x=35

Hope this helps

6 0
2 years ago
Read 2 more answers
Enter the next three numbers of the repeating decimal produced by the
Tanya [424]

Answer:

The next three numbers are; 2,8, and 5.

Step-by-step explanation:

7 0
3 years ago
If the difference of two numbers is even then so is their sum.
Nutka1998 [239]

Answer and explanation:

Statement - If the difference of two numbers is even then so is their sum.

Let the two even numbers be '2m' and '2n' with m and n are integers.

The difference of two number is

2m-2n=2(m-n)

Now, The sum of the numbers is

2m+2n=2(m+n)

Let m+n=k where k is an integer

Then, 2m+2n=2k which is also an even number as 2 is multiplied with it.

So, If the difference of two numbers is even then so is their sum.

For example -

Let two even number 2 and 4.

The difference is 4-2=2, 2 is even.

The sum is 4+2=6, 6 is even.

4 0
3 years ago
Solve the 3 × 3 system shown below. Enter the values of x, y, and z. X + 2y – z = –3 (1) 2x – y + z = 5 (2) x – y + z = 4 (3)
Svet_ta [14]
<h2>Answer:</h2>

\boxed{x=1, \y=-1, \ z=2}

<h2>Step-by-step explanation:</h2>

We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:

Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\~~ x&-~~~~~ y&+~~~~ z&~=~4\end{array}

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&-~~~3~ y&+~~2~ z&~=~7\end{array}

Step 3: Let's multiply second equation by −35, Next, add the result to the third equation. Therefore:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&&+~~\frac{ 1 }{ 5 }~ z&~=~\frac{ 2 }{ 5 }\end{array}

Step 4: solve for z, then for y, then for x:

\frac{ 1 }{ 5 } ~ z & = \frac{ 2 }{ 5 } \\ \\ \boxed{z & = 2}

-5y+3z &= 11\\-5y+3\cdot 2 &= 11\\ \\ \boxed{y &= -1}

By substituting y=-1 \ and \ z=2 into the first equation, we get the x. So:

x+2(-1)-2=-3 \\ \\ x-2-2=-3 \\ \\ \boxed{x=1}

6 0
3 years ago
Read 2 more answers
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