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bonufazy [111]
3 years ago
8

I know the answer to it, it's a...however I need an explanation onto why it's a.​

Mathematics
1 answer:
KonstantinChe [14]3 years ago
4 0

Answer:

You're right

Step-by-step explanation:

Pythagorean Theorem

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Please help!
Mandarinka [93]

Answer:0.11111111111

Step-by-step explanation:0.1 with a repeating decimal over the 1 because when you multiply 1/3 by 1/3 thats what you get.

8 0
3 years ago
If f(x) = 3 – x2, find f(-2).
Rufina [12.5K]

Answer:

f(- 2) = - 1

Step-by-step explanation:

To evaluate f(- 2) substitute x = - 2 into f(x) , that is

f(- 2) = 3 - (- 2)² = 3 - 4 = - 1

4 0
3 years ago
What is the range of the data below?<br>100<br>105<br>110<br>115<br>120<br>125<br>A 2 B 5 C 12 D 13​
MrMuchimi

Answer:

ifk

Step-by-step explanation:

8 0
3 years ago
A rectangle on a coordinate plane is translated 5 units up and 3 units to the left. Which rule describes the trar
Citrus2011 [14]

Answer:

(x, y) → (x - 3, y + 5 )

Step-by-step explanation:

A shift of 3 units to the left means subtract 3 from the original x- coordinate.

A shift of 5 units up means add 5 to the original y- coordinate.

Thus the rule representing the translation is

(x, y ) → (x - 3, y + 5 )

6 0
3 years ago
Read 2 more answers
(12x + y + z = 26
mel-nik [20]

Option D. D has the matrix of constants [[12], [11], [4]].

Step-by-step explanation:

Step 1:

With the given equations, we can form matrices to represent them.

The coefficients of x, y, and z form a matrix of order 3 ×3, the variables x, y, and z form a matrix of order 1 ×3 and the constants form a matrix of order 1 ×3.

Step 2:

The linear system A is represented as

\left[\begin{array}{ccc}12&1&1\\1&-11&0\\1&-1&4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}26\\17\\23\end{array}\right].

Step 3:

The linear system B is represented as

\left[\begin{array}{ccc}4&1&1\\1&-11&0\\1&-1&12\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}23\\17\\26\end{array}\right].

Step 4:

The linear system C is represented as

\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}4\\11\\12\end{array}\right].

Step 5:

The linear system D is represented as

\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}12\\11\\4\end{array}\right].

Step 6:

Of the four options, the linear system D has the matrix of constants [[12], [11], [4]]. So the answer is option D. D.

4 0
3 years ago
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