<span>distance=6390km; time=9 hrs; rate=710kph
With the wind Data:
distance=5150km; time=5hrs; rate=1030kph
EQUATIONS:
airspeed+jetstream=1030
airspeed-jetstream=710
Subtract these equations to get:
2jetstream=320kph
jetstream=160mph </span>
18 !
27/x = 12/8
Cross multiply and then solve
Answer:
(3y+2)(y+7)
Step-by-step explanation:
I think you meant (y+7)+3y(y+7)+(y+7). Anyways, we have to count the number of (y+7) there are. The first term tells us we have 1 group. The second term tell us we have 3y groups. The last term tells us we have 1 group. Therefore we have 1+3y+1 groups of y+7 which gives us (3y+2)(y+7)
Answer:
Where is the figure?????????????
Answer:
x +2xπ5+2f
Step-by-step explanation:
This is the wrong answer lol
