1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
o-na [289]
3 years ago
7

a department store buys 500 shirts at a cost of 3,000 and sells them at a selling price of $10 each. find the percent markup

Mathematics
2 answers:
natita [175]3 years ago
7 0

3000/500 = 6

Each shirt costs 6 dollars

percent markup

(new - original)/original

(10-6)/6

4/6

66.666666666%

66 2/3 % mark up

Rainbow [258]3 years ago
4 0

Answer:


Step-by-step explanation:10



You might be interested in
Trim earnings 28.50 tutoring for 3hours write an equation relating her earnings m to the number of hours h she tutors assuming t
neonofarm [45]

Answer:

142

Step-by-step explanation:

28.59 times 5 bc 3 plus 2 is 5

5 0
3 years ago
Solve usuing synthetic divison and list the steps/explain answer.<br> (7m^(3)+16m^(2)-7m+27)-:(m+3)
zloy xaker [14]

Answer:

7m² - 5m + 8 + 3/(m+3)

Step-by-step explanation:

7m³+16m²-7m+27

(7m³+21m²-5m²-15m+8m+24+3)/(m+3)

[7m²(m+3) - 5m(m+3) + 8(m+3) + 3]/(m+3)

7m² - 5m + 8 + 3/(m+3)

6 0
3 years ago
Read 2 more answers
You buy milk at $2.48 per gallon. One portion of oatmeal requires 4 ounces of milk. How much does the milk for one portion cost?
xeze [42]
7.75 is your answer
hope this helps
3 0
3 years ago
I NEED HELP ASAP PLS
maksim [4K]
Y=2/1x

Explanation:You start at -4 from the y and go to 6.So that becomes 10. Then you start at -2 from the x then go to 3 which mean you moved 5.So 10/5 simplified is is 2/1
8 0
2 years ago
ASAP! I WILL MARK BRAINLIST ! 38 POINTS STEP BY STEP PLEASEE STEPS NEEDED!
marta [7]

Answer:

A) Length = 110.4 mm and width = 62.1 mm

B) A = 6855.84 mm²

C) length = 114.7 mm

width = 55.8 mm

Area = 6400.26 mm²

D) Screen with aspect ratio of 16:9 is bigger

Step-by-step explanation:

A) We are told that the aspect ratio of the phone screen = 16:9. This means that the ratio of the length to the width of the screen is 16:9.

To find the side length, we will say that;

length = 16x

width = 9x

Thus, since the edges are perpendicular, then we can use pythagoras theorem since we know that the diagonal is 127 mm

Thus;

(16x)² + (9x²)] = 127²

256x² + 81x² = 16129

337x² = 16129

x² = 16129/337

x = √(16129/337)

x = 6.9

Thus;

length = 16x = 16 × 6.9 = 110.4 mm

width = 9x = 9 × 6.9 = 62.1 mm

Length = 110.4 mm and width = 62.1 mm

B) area of screen is;

A = length × width

A = 110.4 × 62.1

A = 6855.84 mm²

C) We are told that the aspect ratio is now 18.5:9.

Thus;

length = 18.5x

width = 9x

Thus;

(18.5x)² + (9x²)] = 127²

342.25x² + 81x² = 16129

423.25x² = 16129

x² = 16129/423.25

x = √(16129/423.25)

x = 6.2

length = 18.5x = 18.5 × 6.2 = 114.7 mm

width = 9x = 9 × 6.2 = 55.8 mm

Area = 114.7 × 55.8 = 6400.26 mm²

D) Screen with aspect ratio of 16:9 is bigger

8 0
3 years ago
Other questions:
  • Help pls ASAP <br><br><br> Thanks
    11·1 answer
  • What term is 1/1024 in the geometric sequence,-1,1/4,-1/6..?
    6·1 answer
  • The function h(x) is given below. h(x) = {(3, –5), (5, –7), (6, –9), (10, –12), (12, –16)} Which of the following gives h–1(x)?
    5·2 answers
  • Which expression can be used to find the sum of the polynomials? (9 – 3x2) + (–8x2 + 4x + 5)
    6·1 answer
  • Joanne buys a rectangle at rug rug with an area of 35/4 square meters. The length of the rug is 7/2 meters. What is the width, i
    15·2 answers
  • A rectangle has a length of 72 cm and a width of 56 cm. The other rectangle has the same area as this one, but its width is 21cm
    11·1 answer
  • HELP PLEASE QUICK!!!!!!!!!!!!
    10·1 answer
  • Pls help asap no wrong answer pls
    10·2 answers
  • Order the numbers from least to greatest. -0.25,1-5,0.3​
    8·1 answer
  • Evaluate the expression 6/5x when x=20
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!