Ok
first of all, for q(x)/p(x)
if the degree of q(x) is less than the degree of p(x),then the horizontal assemtote is 0
then simplify
any factors you factored out is now a hole, remember them
to find the vertical assemtotes of a function, set the SIMPLIFIED denomenator equal to 0 and solve
so
y=(x-5)/(x^2-1)
q(x)<p(x)
horizontal assemtote is y=0
no factors to simplify so no holes
set denomenator to 0 to find vertical assemtote
x^2-1=0
(x-1)(x+1)=0
x-1=0
x=1
x+1=0
x=-1
the horizontal assemtotes are x=1 and -1
Answer: -44
Step-by-step explanation: PEMDAS(Parenthesis; Exponent; Multiply; Divide; Add; Subtract)
First you multiply the seven with the other seven to get 49. The problem will look like this: (-3) + 8 - 49. Now just add the -3 and 8. You'd get 5.
Now the problem looks like this: 5 - 49. And you then get -44.
Answer is: 2x=12, 14, 16, and 18
Answer:
A.
Step-by-step explanation:
Plugging in all the values into the equation, only A holds a true statement.
Answer:
-10x +4
Step-by-step explanation:
