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docker41 [41]
3 years ago
13

Kaitlin runs each lap in 7 minutes. She will run more than 8 laps today. What are the possible numbers of minutes she will run t

oday?
Use t for the number of minutes she will run today.
Write your answer as an inequality solved for t.
Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
7 0

Answer:

Step-by-step explanation:

Time is t

1 lap in 7 minutes

Morethan 8 laps in more than 8×7 minutes that is more than 48 minutes

Don't exactly get the last bit sorry

ivolga24 [154]3 years ago
6 0

Answer:

if she runs more than 8 laps and each lap is 7 minutes she will run more than 56 minutes

she will run 56 minutes t

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help please! the pair of figures to the right are similar. what is the ratio of the perimeters and the ratio of the areas?
jasenka [17]

Answer:

Perimeters = 3 in : 7 in

Areas = 9 in² : 49 in²

Step-by-step explanation:

    <em>If the figures are </em><em>squares</em><em>, and the measurements are the length of that sides (as you have said), then we will do the following. </em>

[The left square]

P = 4a

P = 4(15)

P = 60 in

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A = a²

A = 15²

A = 225 in²

[The right square]

P = 4a

P = 4(35)

P = 140 in

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A = a²

A = (35)²

A = 1,225 in²

[Simplifying ratios]

Perimeters = 60 in : 140 in

Perimeters = 6 in : 14 in

Perimeters = 3 in : 7 in

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Areas = 225 in² : 1,225 in²

Areas = 45 in² : 245 in²

Areas = 9 in² : 49 in²

4 0
3 years ago
Given the position of the particle, what the position(s) of the particle when it’s at rest
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The position function of a particle is given by:

X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t

The velocity function is the derivative of the position:

\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}

The particle will be at rest when the velocity is 0, thus we solve the equation:

2t^2-9t-18=0

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Substituting:

\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}

We have two possible answers:

\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

undefined

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