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Naya [18.7K]
3 years ago
8

Scientific notation of 864,000,000,000,000

Mathematics
2 answers:
sineoko [7]3 years ago
5 0

Answer:

8.64x10 to the power of 14


Step-by-step explanation:


yuradex [85]3 years ago
5 0

Answer:

Its 8.64x10 to the power of 14



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This level is locked
Sphinxa [80]

Answer:

-b.h

Step-by-step explanation:

-5/6=-0.8 and 2/1=2

so it is -0.8-2=-2.8

2=b

8=h

5 0
3 years ago
Choose the correct answer in each number.
4vir4ik [10]

Answer:

A

B

A

C

D

C

A

B

B

D

Step-by-step explanation:

7 0
2 years ago
Simplify the expression (22+19b) +7
Evgesh-ka [11]

Answer:

there is no multiplication, so just 29+ 19b

7 0
3 years ago
Read 2 more answers
Ramon earns $1,815 each month and pays $53.20 on electricity. To the nearest tenth of a percent, what percent of Ramon's earning
pashok25 [27]
Answer should be 3.06% of his money.
5 0
3 years ago
Use the denition of the derivative to find f 0 (3), where f (x) = 3x+5 / 2x−1
Crazy boy [7]

Answer:

f'(3)= -\frac{13}{25}

Step-by-step explanation:

We are asked to find f'(3) of function f(x)=\frac{3x+5}{2x-1} using definition of derivatives.

Limit definition of derivatives:

f'(x)= \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}

Let us find f(3+h) and f(3).

f(3+h)=\frac{3(3+h)+5}{2(3+h)-1}

f(3+h)=\frac{9+3h+5}{6+2h-1}\\\\f(3+h)=\frac{3h+14}{2h+5}

f(3)=\frac{3(3)+5}{2(3)-1}

f(3)=\frac{9+5}{6-1}\\\\f(3)=\frac{14}{5}

Substituting these values in limit definition of derivatives, we will get:

f'(3)= \lim_{h \to 0} \frac{f(3+h)-f(3)}{h}

f'(3)= \lim_{h \to 0} \frac{\frac{3h+14}{2h+5}-\frac{14}{5}}{h}

Make a common denominator:

f'(3)= \lim_{h \to 0} \frac{\frac{(3h+14)*5}{(2h+5)*5}-\frac{14(2h+5)}{5(2h+5)}}{h}

f'(3)= \lim_{h \to 0} \frac{\frac{5(3h+14)-14(2h+5)}{5(2h+5)}}{h}

f'(3)= \lim_{h \to 0} \frac{5(3h+14)-14(2h+5)}{5h(2h+5)}

f'(3)= \lim_{h \to 0} \frac{15h+70-28h-70}{5h(2h+5)}

f'(3)= \lim_{h \to 0} \frac{-13h}{5h(2h+5)}

Cancel out h:

f'(3)= \lim_{h \to 0} \frac{-13}{5(2h+5)}

f'(3)= \frac{-13}{5(2(0)+5)}

f'(3)= \frac{-13}{5(5)}

f'(3)= -\frac{13}{25}

Therefore, f'(3)= -\frac{13}{25}.

8 0
3 years ago
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