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drek231 [11]
3 years ago
15

The volume of a cube with edge length e is modeled by the function v(e)=e3. Find a function for the edge of a cube given its vol

ume. HELP PLEASE!!!!

Mathematics
1 answer:
dsp733 years ago
4 0
V(e) = e^3.

For any value of e, (the edge length), just cube it to get the volume. Easy

V(-2) = -8
V(-1) = -1
V(0) = 0
V(1) = 1
V(2) = 8
V(3) would be 27...etc

It doesn't make sense to use a negative or zero value for e (since you can't have a length like that), so technically there should be a restriction of e > 0.

To find the edge length given the volume, we would just solve for e.

V = e³
Take the cube root of each side...
∛V = ∛e³
∛V = e

Write as e(V) = ∛V.
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The length of the box is 2x - 2 and the width is x - 5. Find the perimeter. (HINT: p= 2L + 2W) Choose one.
trasher [3.6K]

Answer:

Option D: 6x-14 is the correct answer.

Step-by-step explanation:

Given that:

Length of the box = L = 2x-2

Width of the box = W = x-5

Perimeter is defined by the sum of length of all sides of the box.

Perimeter of the box = P = 2L + 2W

Perimeter of box = 2(2x-2) + 2(x-5)

Perimeter = 4x-4+2x-10

Perimeter = 6x-14

The perimeter of the box is 6x-14.

Hence,

Option D: 6x-14 is the correct answer.

6 0
3 years ago
In order to evaluate 7 sec(θ) dθ, multiply the integrand by sec(θ) + tan(θ) sec(θ) + tan(θ) . 7 sec(θ) dθ = 7 sec(θ) sec(θ) + ta
Maurinko [17]

Answer:

\int {7 \sec(\theta) } \, d\theta = 7\ln(\sec(\theta) + \tan(\theta)) + c

Step-by-step explanation:

The question is not properly formatted. However, the integral of \int {7 \sec(\theta) } \, d\theta is as follows:

<h3></h3>

\int {7 \sec(\theta) } \, d\theta

Remove constant 7 out of the integrand

\int {7 \sec(\theta) } \, d\theta = 7\int {\sec(\theta) } \, d\theta

Multiply by 1

\int {7 \sec(\theta) } \, d\theta = 7\int {\sec(\theta) * 1} \, d\theta

Express 1 as: \frac{\sec(\theta) + \tan(\theta) }{\sec(\theta) + \tan(\theta)}

\int {7 \sec(\theta) } \, d\theta = 7\int {\sec(\theta) * \frac{\sec(\theta) + \tan(\theta) }{\sec(\theta) + \tan(\theta)}} \, d\theta

Expand

\int {7 \sec(\theta) } \, d\theta = 7\int {\frac{\sec^2(\theta) + \sec(\theta)\tan(\theta) }{\sec(\theta) + \tan(\theta)}} \, d\theta

Let

u = \sec(\theta) + \tan(\theta)

Differentiate

\frac{du}{d\theta} = \sec(\theta)\tan(\theta) + sec^2(\theta)

Make d\theta the subject

d\theta = \frac{du}{\sec(\theta)\tan(\theta) + sec^2(\theta)}

So, we have:

\int {7 \sec(\theta) } \, d\theta = 7\int {\frac{\sec^2(\theta) + \sec(\theta)\tan(\theta) }{u}} \,* \frac{du}{\sec(\theta)\tan(\theta) + sec^2(\theta)}

Cancel out \sec(\theta)\tan(\theta) + sec^2(\theta)

\int {7 \sec(\theta) } \, d\theta = 7\int {\frac{1}{u}} \,du}}

Integrate

\int {7 \sec(\theta) } \, d\theta = 7\ln(u) + c

Recall that: u = \sec(\theta) + \tan(\theta)

\int {7 \sec(\theta) } \, d\theta = 7\ln(\sec(\theta) + \tan(\theta)) + c

8 0
3 years ago
The librarian has 94 books to organize. He wants to put 5 books on some shelves and 6 books on other shelves. How could he arran
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2820 books to arrange
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Sonnie deposited $2,500 into an account that earns simple interest. After 5 years, she earned $375 in interest. What was the int
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Answer:

  3%

Step-by-step explanation:

The interest on the account is given by the simple interest formula:

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where I is the interest, P is the principal invested, r is the annual rate, and t is the number of years

  375 = 2500r(5) . . . . . . using the given values in the formula

  375/12500 = r = 0.03 . . . . . divide by the coefficient of r

Sonnie's account had a 3% interest rate.

4 0
3 years ago
What best describes the expression 9(x +7)​
Lisa [10]

Answer:

9x + 63

Step-by-step explanation:

9 x X = 9x

9 x 7 = 63

9x + 63

6 0
3 years ago
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