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Gnesinka [82]
3 years ago
8

Can someone help me with this problem pls

Mathematics
1 answer:
Talja [164]3 years ago
8 0
A. Slope = 2
b. Slope = 2/3 or 0.66

(Slope = change in y / change in x)
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Find the equation of the line that contains the point (4,-2) and is perpendicular to the line y=-2x+8.
snow_tiger [21]

Answer:

\frac{1}{2} x - 4

Step-by-step explanation:

Perpendicular lines will have slopes that are the multiplicative additive inverse of each other: a line with slope 3/4 is perpendicular to a line with slope -4/3, for example.  You need a line that is perpendicular to a line with slope -2 (reading that from the -2 in the -2x portion of the given equation, which is written in slope-intercept form), so your new line must have slope +1/2.

With the slope and a point, we can come up with an equation using this formula:

y - y-coordinate = slope (x - x-coordinate)

So we have y - (-2) = 1/2 (x - 4).

Simplify the equation:  y + 2 = 1/2 x - 2

Subtract 2 from both sides: y + 2 - 2 = 1/2 x - 2 - 2

Simplify: y = 1/2 x - 4.

4 0
2 years ago
10-2+3x19-8= first to answer will get brainlyest
KIM [24]
57 because of pemdas....
3 0
2 years ago
Read 2 more answers
Write the phrase as a mathematical expression. Use x as the variable.
11111nata11111 [884]

Answer:

4(2x+7) which is equal to 8x+28

4 0
1 year ago
What makes apparent magnitude different from absolute brightness? Give an example in your response.
Lapatulllka [165]
Apparent magnitude isn’t the actual brightness, it’s what the brightness appears to be from earth, absolute brightness is the actual brightness an example is our sun it appears bright on earth but in space it is so much more brighter
8 0
2 years ago
Answer ,how to do it.
guapka [62]

Answer:

<u>The system has two solutions:</u>

<u>x₁ = 5  ⇒ y₁ = -10</u>

<u>x₂ = -2 ⇒ y₂ = 11</u>

Step-by-step explanation:

Let's solve the system of equations, this way:

y = -3x + 5

y = x ² - 6x - 5

Replacing y in the 2nd equation:

y = x ² - 6x - 5

-3x + 5 = x ² - 6x - 5

x ² - 3x - 10 = 0

Solving for x, using the quadratic formula:

(3 +/- √(9 -4 * 1 * -10))/2 * 1

(3 +/- √9 + 40)/2

(3 +/- √49)/2

(3 +/- 7)/2

x₁ = 10/2 = 5

x₂ = -4/2 = -2

x₁ = 5  ⇒ y₁ = -10

x₂ = -2 ⇒ y₂ = 11

<u>As we can see the system has two different solutions</u>

8 0
3 years ago
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