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raketka [301]
3 years ago
10

The length of a rectangular patio is 4 feet less than three times it's width. The area of the patio is 160 square feet. Find the

dimensions of the patio.
Mathematics
1 answer:
Levart [38]3 years ago
3 0

Step-by-step explanation:

The length of a rectangular patio is 4 feet less than three times it's width. The area of the patio is 160 square feet. Find the dimensions of the patio.

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Which of the following is the complete list of roots for the polynomial function fx= (x^2
julia-pushkina [17]

6x3+49x2+126x+104 (I just simplified it, if it is incorrect I'm sorry I didnt understand what you were asking -,^-)

8 0
3 years ago
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Can someone help me with both I will mark u brilliant
OLEGan [10]

Answer: 22

Step-by-step explanation:

Add everything together (264) and divide by 12 the amount of numbers there are to find the mean or the average

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2 years ago
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The diameter of a tire is 2.5 ft. Use this measurement to answer parts a and b. Show all work to receive full credit
Alla [95]

Answer:

The answer is below

Step-by-step explanation:

The diameter of a tire is 2.5 ft. a. Find the circumference of the tire. b. About how many times will the tire have to rotate to travel 1 mile?

Solution:

a) The circumference of a circle is the perimeter of the circle. The circumference of the circle is the distance around a circle, that is the arc length of the circle. The circumference of a circle is given by:

Circumference = 2π × radius; but diameter = 2 × radius. Hence:

Circumference = π * diameter.

Given that diameter of the tire = 2.5 ft:

Circumference of the tire = π * diameter = 2.5 * π = 7.85 ft

b) since the circumference of the tire is 7.85 ft, it means that 1 revolution of the tire covers a distance of 7.85 ft.

1 mile = 5280 ft

The number of rotation required to cover 1 mile (5280 ft) is:

number of rotation = \frac{5280\ ft}{7.85\ ft\ per\ rotation}=672\ rotations\\\\\\

4 0
3 years ago
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I’ll give brainliest!
iren [92.7K]

Answer:

okay ans is A(w)=w2+5w-1/8piw2

6 0
2 years ago
The faces on a number cube are labled 1,2,2,3,4, and 5the number cube is rolled 114 times how many times would you expect the nu
Mrac [35]

Given:

The faces on a number cube are labeled 1,2,2,3,4, and 5.

The number cube is rolled 114 times.

To find:

How many times would you expect the number 2 to appear?

Solution:

We have,

Total outcomes = 1,2,2,3,4, and 5.

Number of total outcomes = 6

Favorable outcomes = 2 and 2

Number of favorable outcomes = 2

The probability of getting 2 is:

P(2)=\dfrac{\text{Number of favorable outcomes}}{\text{Number of total outcomes}}

P(2)=\dfrac{2}{6}

P(2)=\dfrac{1}{3}

Now, the expected number of times when 2 to appear is:

E(x)=114\times P(2)

E(x)=114\times \dfrac{1}{3}

E(x)=38

Therefore, the expected number of times is 38.

4 0
2 years ago
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