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malfutka [58]
3 years ago
6

Jacob wants to make a graph to show the relationship between temperatures in Fahrenheit and degrees Celsius. He plots the follow

ing points: (11, −11.7), (15, −9.4), (25, −3.9), (35, 1.7), (45, 7.2) He uses the following steps to plot the graph: Label origin as (0, 0). On x-axis, label Temperature in Fahrenheit. On y-axis, label Temperature in degrees Celsius. The scale on x-axis starts from 0 and goes up to 700 at intervals of 20. The scale on the y-axis starts from −12 and goes up to 12 at intervals of 2. Which of the following best describes the graph? It will not be spread out horizontally across the entire coordinate plane because in Step 4, Jacob selected an incorrect scale on the x-axis. It will not be spread out vertically across the entire coordinate plane because in Step 5, Jacob selected an incorrect scale on the y-axis. It will not be spread out horizontally across the entire coordinate plane because in Step 2, Jacob plotted Fahrenheit instead of Celsius on the axis. It will not be spread out vertically across the entire coordinate plane because in Step 3, Jacob plotted Celsius instead of Fahrenheit on the y-axis.
Mathematics
2 answers:
mr_godi [17]3 years ago
5 0
We have:
 Label origin as (0, 0).
 On x-axis, label Temperature in Fahrenheit.
 On y-axis, label Temperature in degrees Celsius.
 Therefore,
 C = f (F). 
 Then,
 The scale on x-axis starts from 0 and goes up to 700 at intervals of 20.
 Therefore, each grid:
 xi = 700/20 = 35 
 The scale on the y-axis starts from -12 and goes up to 12 at intervals of 2 
 Therefore, each grid:
 yi = 12/2 = 6.
 answer:
 It will not spread horizontally across the entire coordinate plane because in Step 4, Jacob selected an incorrect scale on the x-axis.
Harlamova29_29 [7]3 years ago
5 0
 It won´t spread horizontally across the coordinate plane because in Step 4, Jacob selected an incorrect scale on the x-axis.

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Answer:

a) 56% probability you get a female student.

b) 30.33% probability that both are female

c) 43.52% probability that you get 2 female and one male

d) 18.26% probability that you get 1 female and 3 male

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in whih the students are chosen is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

a. Pick one student randomly, what is the probability you get a female student?

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1 female student from a set of 14. So

D = C_{14,1} = \frac{14!}{1!13!} = 14

Total outcomes:

1 student from a set of 25. So

T = C_{25,1} = \frac{25!}{1!24!} = 25

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P = \frac{D}{T} = \frac{14}{25} = 0.56

56% probability you get a female student.

b. Pick two students randomly, what is the probability that both are female?

Desired outcomes:

2 female students, from a set of 14. So

D = C_{14,2} = \frac{14!}{2!12!} = 91

Total outcomes:

2 students from a set of 25. So

T = C_{25,2} = \frac{25!}{2!23!} = 300

Probability:

P = \frac{D}{T} = \frac{91}{300} = 0.3033

30.33% probability that both are female

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Desired outcomes:

2 female students, from a set of 14, and one male student, from a set of 11. So

D = C_{14,2}*C_{11,1} = \frac{14!}{2!12!}*\frac{11!}{1!10!} = 1001

Total outcomes:

3 students from a set of 25. So

T = C_{25,3} = \frac{25!}{3!22!} = 2300

Probability:

P = \frac{D}{T} = \frac{1001}{2300} = 0.4352

43.52% probability that you get 2 female and one male

d. Pick four students randomly, what is the probability that you get 1 female and 3 male?

Desired outcomes:

1 female student, from a set of 14, and 3 male students, from a set of 11.

D = C_{14,1}*C_{11,3} = \frac{14!}{1!13!}*\frac{11!}{8!3!} = 2310

Total outcomes:

4 students from a set of 25. So

T = C_{25,4} = \frac{25!}{4!21!} = 12650

Probability:

P = \frac{D}{T} = \frac{2310}{12650} = 0.1826

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