The solution for x in the equation 3ax - n/5 = -4 is x = -4/3a + n/15a.
<h3>What is the solution for x in the given equation?</h3>
3ax - n/5 = -4
To solve for x, isolate the term that contains x.
3ax - n/5 = -4
3ax = -4 + n/5
Divide each term by the coefficient of x and simplify
3ax/3a = -4/3a + (n/5)/3a
x = -4/3a + (n/5)/3a
multiply (n/5) by the reciprocal of 3a
x = -4/3a + (n/5) × 1/3a
x = -4/3a + n/15a
Therefore, the solution for x in the equation 3ax - n/5 = -4 is x = -4/3a + n/15a.
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From the series, it can be deduced that the sum of the first two terms will be 18.
<h3>How to calculate the series</h3>
From the information given, it was stated that the transport charge starts with a minimum charge of R8 and thereafter it was increased by R2 for each kilometre.
The series is also given as S. = 8 + 10 + 12 + 14 +... Therefore, the sum of the first two terms will be:
= 8 + 10
= 18
Expressing T2 in terms of S, and S2 will be T2 = S + S2.
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Answer:
494018
Step-by-step explanation:
you are trying to find the diameter of the circle, it is usually half the length of a radius, but since 497 squared is how long a radius is (unless the question asked that the area if 497 inches squared), i can't really give you a clear answer, but the diameter is 247009 times 2 which is 494018
Answer:
5.7 units
Step-by-step explanation:
The distance from point P to QS is the distance from point P (1, 1) to the point of interception R(-3, 5).
Use distance formula to calculate distance between P and R:

Let,


Plug in the values into the formula.




(to nearest tenth)
I think it’s a carrot 100