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3 years ago

6

Find the selling price of each item.

1 answer:

frutty [35]3 years ago

5 0

Answer:

9.075

Step-by-step explanation:

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What is the length of the side labeled x cm?

UkoKoshka [18]

When we know 2 angles and one side, we use the Law of Sines.
First we need to find that third angle.
Angle A =
180 -41 -62 = 77 degrees

The Law of Sines states that

side a / Sine (A) = side x / Sine (X)
14 / Sine (77) = side x / Sine (41)

14 * Sine (41) / Sine (77) = side x

side x = 14 * 0.65606 / 0.97437
<span>side x = 9.18484 / 0.97437
</span>
<span> <span> <span> side x = 9.4264396482 </span> </span> </span>

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3 years ago

Find YQ if MQ = 3x-3 and YQ = 2x-6.

Alina [70]

Answer:

• Assume Q is a mid point of line MY

${ \underline{ \sf{ \: _{l} M \: \: \: \: \: \: \: \: _{l} Q \: \: \: \: \: \: \: \: _{l}Y}}}$

• Then, MQ = YQ

${ \rm{(3x - 3) = (2x - 6)}} \\ \\ { \rm{3x - 2x = - 6 + 3}} \\ \\ { \boxed{ \rm{ \: x = - 3 \: }}}$

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2 years ago

a pentagon is a regular pentagon that has 5 sides, so each side has the same length that is (x - 1.5)cm. The perimeter is 22.5 c

Ivanshal [37]

Answer:

Step-by-step explanation:

5(x - 1.5) = 22.5

5x - 7.5 = 22.5

5x = 15

x = 3

8 0

2 years ago

On the first day, you pay $5 for 2 boxes of popcorn.

ahrayia [7]

Answer:

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Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

In the figure, triangle CAE is an enlargement of triangle CBD with scale factor of 4/3. The area of the smaller triangle is 9cm2

balandron [24]

Answer:

16 cm^2

Step-by-step explanation:

Given

$\triangle CAE$ -- Bigger Triangle

$\triangle CBD$ -- Smaller Triangle

$k = \frac{4}{3}$ --- Scale factor

Area of CBD = 9

Required

Determine the area of CAE

The area of triangle CBD is:

$A_1 = \frac{1}{2}bh$

$\frac{1}{2}bh = 9$

The area of CAE is:

$A_2 = \frac{1}{2}BH$

Where:

$B = \frac{4}{3}b$ and

$H = \frac{4}{3}h$

The above values is the dimension of the larger triangle (after dilation).

So, we have:

$A_2 = \frac{1}{2}*\frac{4}{3}b * \frac{4}{3} * h$

$A_2 = \frac{1}{2}*\frac{4}{3} * \frac{4}{3} *b* h$

$A_2 = \frac{1}{2}*\frac{16}{9} *b* h$

Re-order

$A_2 = \frac{16}{9}*\frac{1}{2}* b* h$

$A_2 = \frac{16}{9}*\frac{1}{2}bh$

Recall that:

$\frac{1}{2}bh = 9$

$A_2 = \frac{16}{9}*9$

$A_2 = 16$

Hence, the area is 16 cm^2

3 0

3 years ago