Question

Scott threw the javelin 3 times farther than daniel threw the javelin. what is an expression for the distance scott threw the javelin?

Answer 1

An expression for the distance Scott threw the javelin is, x = 3y

For given question,

Let x be the distance for Scott threw the javelin and y be the distance for Daniel threw the javelin.

We have been given a statement 'Scott threw the javelin 3 times farther than Daniel threw the javelin.'

We need to write given statement as a mathematical expression.

First we rewrite given statement as,

Scott threw the javelin 3 times farther than Daniel threw the javelin.

the distance Scott threw the javelin is 3 times the distance Daniel threw the javelin

⇒ x = 3 × y

Therefore, an expression for the distance Scott threw the javelin is,

x = 3y

Learn more about an expression here:

brainly.com/question/14961928

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