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3 years ago

Find the distance between the points (−8, 5) and (7, −3).

Mathematics

1 answer:

dmitriy555 [2]3 years ago

7 0

Answer:

Step-by-step explanation:

use distance formula $\sqrt{(x_1-x_2)^{2}+(y_1-y_2)^{2} }$

$\sqrt{(7-(-8))^{2}+((-3)-5)^{2} }$

simplify

$\sqrt{(7+8)^{2}+(-3-5)^{2} }$

$\sqrt{(15)^{2}+(-8)^{2} }$

$\sqrt{225+64}$

$\sqrt{289}$

solve the square root

$17$

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I need help with slope

Serggg [28]

Answer:

1. (AB) y = 2/3x + -4

Step-by-step explanation:

Formula - y = m(x) + (y-intercept)

m = rise / run

"run = horizontal (left and right)

rise = vertical (up and down)"

the y intercept is always going to be where y is 0 at. (x, y) you will use your x to determine the intercept

So lets use your first question as an example

1. (AB) y = m(x) + (y-int)

y = m(x) + (-4)

the point goes to the right 6 points and goes up 4 points (rise / run)

y = 4/6(x) + (-4)

You can round up the fraction to 2/3

y = 2/3(x) + -4

6 0

2 years ago

If 3 times a certain number is increased by 4 the result is 28. What is the number?

Minchanka [31]

3x+4=28 because 3 times an unknown number was mentioned first and mentioned together so they will be together, increased by 4 is +4 and comes after, the result of is the same as equals so you put the equals sign and whatever number they gave after.

8 0

3 years ago

Find the distance and displacement for the following figures :

Vinil7 [7]

The figure (i) have a distance of 15.996 meters and a displacement of 13.892 meters and (ii) a distance of 480 centimeters and a displacement of 339.411 centimeters

<h3>How to find the distance and displacement in each trajectory</h3>

The distance is the sum of the lengths that form a trajectory and the displacement is the distance between the initial and final point of a trajectory. Then, we have the following results for each case:

Case I

Distance

d = 5 m + 0.5π · (7 m)

d ≈ 15.996 m

Displacement

$D = \sqrt{(12\,m)^{2}+(7 m)^{2}}$