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3 years ago

Find the distance between the points (−8, 5) and (7, −3).

Mathematics

1 answer:

dmitriy555 [2]3 years ago

7 0

Answer:

Step-by-step explanation:

use distance formula $\sqrt{(x_1-x_2)^{2}+(y_1-y_2)^{2} }$

$\sqrt{(7-(-8))^{2}+((-3)-5)^{2} }$

simplify

$\sqrt{(7+8)^{2}+(-3-5)^{2} }$

$\sqrt{(15)^{2}+(-8)^{2} }$

$\sqrt{225+64}$

$\sqrt{289}$

solve the square root

$17$

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Nine million ninety thousand nine hundred and ninety-nine ten-thousandths

vfiekz [6]

9,090,900.0099 is the answer.

8 0

3 years ago

two girls went shopping and spent $334. one girls spent $16 more thent the other girl did. how much did each spend

Taya2010 [7]

I will try my best to assist you with your question ,

First we must divide the amount by 2

334/2 = 167

Now we add 16

167 + 16=183

So, the girl spent $183

Wow, she is spoiled!

Hope I helped!

Good Luck!

3 0

3 years ago

Suppose 6 of 15 students in a grade-school class develop influenza where 20 percent of grade-school students nationwide develope

Snowcat [4.5K]

I am not sure what the question is here. I can tell you how to find the percent of kids that developed influenza in that class. We can compare it to the 20% of students nationwide. There could many different questions that stem from the piece of information you gave.

To find the percent of kids that developed influenza in that class do 6÷15 which gives you
.4 and written as a percent would be 40%.

Please message me if you have any questions! Hope this helps!

6 0

3 years ago

You are at a stall at a fair where you have to throw a ball at a target. There are two versions of the game. In the first

Tomtit [17]

Answer:

$P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729$

And the probability of loss with the first wersion is 0.729

$P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774$

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Alternative 1

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=3, p=0.1)$