Answer:
There can be 14,040,000 different passwords
Step-by-step explanation:
Number of permutations to order 3 letters and 2 numbers (total 5)
(AAANN, AANNA,AANAN,...)
= 5! / (3! 2!)
= 120 / (6*2)
= 10
For each permutation, the three distinct (English) letters can be arranged in
26!/(26-3)! = 26!/23! = 26*25*24 = 15600 ways
For each permutation, the two distinct digits can be arranged in
10!/(10-2)! = 10!/8! = 10*9 = 90 ways.
So the total number of distinct passwords is the product of all three permutations,
N = 10 * 15600 * 90 = 14,040,000
L = 4 + w
perimeter = 38
38 = w + 4 + w
2w = 34
w = 17
L = 4 + 17
L = 21
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Answer: B. Funds need to be easily accessible
This is so you can access it easily without paying a penalty
0.28=0.2+0.08
Or
0.28=2/10+8/100
Or
0.28=(2*1/10)+(8*1/100)
Or
0.28=(2*1/10^1)+(8*1/10^2)
