You run a 100-yd dash in 9.8 seconds. how long would it take you to run a 100-m dash if you run at this same speed?

How do i solve 2+49x4+x

qaws [65]

Answer:

Step by step solution :

STEP1:Equation at the end of step 1

((49 • (x4)) - (2•7x2)) + 1 = 0

STEP 2 :

Equation at the end of step2:

(72x4 - (2•7x2)) + 1 = 0

STEP3:Trying to factor by splitting the middle term

3.1 Factoring 49x4-14x2+1

The first term is, 49x4 its coefficient is 49 .

The middle term is, -14x2 its coefficient is -14 .

The last term, "the constant", is +1

Step-1 : Multiply the coefficient of the first term by the constant 49 • 1 = 49

Step-2 : Find two factors of 49 whose sum equals the coefficient of the middle term, which is -14 .

-49 + -1 = -50 -7 + -7 = -14 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -7 and -7

49x4 - 7x2 - 7x2 - 1

Step-4 : Add up the first 2 terms, pulling out like factors :

7x2 • (7x2-1)

Add up the last 2 terms, pulling out common factors :

1 • (7x2-1)

Step-5 : Add up the four terms of step 4 :

(7x2-1) • (7x2-1)

Which is the desired factorization

Step-by-step explanation:

I have been working on this foe so long so I would appreciate brailyest!!

6 0

3 years ago

Write 75 as a product of prime use index notation when giving your answer

11Alexandr11 [23.1K]

The prime factorization of 75 is 3 × 5 × 5 or 3 x 52.

6 0

1 year ago

Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e^−2

Mekhanik [1.2K]

Answer:

x=1

y=s

z=1

Step-by-step explanation:

(x, y, z)=(1, 0, 1)

Substitute 0 for y

$y = e^{-2t} *sin 4t\\0 = e^{-2t} *sin 4t\\\\0 = e^{-2t} *(\frac{e^{4t}-e^{-4t}}{2j} )\\0 = e^{-2t} *(e^{4t}-e^{-4t} )\\0 = e^{-2t} *e^{4t}*(1-e^{-8t} )\\\\0 = e^{2t}*(1-e^{-8t} )\\\\\\Either \\0 = e^{2t}\\t = -inf\\or\\0 = (1-e^{-8t} )\\(e^{-8t} ) = 1\\ -8t = ln(1) =0\\t=0\\\\$

Confirming if t=0 satisfy the other equation

x = e^−2t cos 4t = e^−2(0)cos(4*0)

= e^(0)cos(0) = 1

z = e^−2t = e^−2(0) = 0

Therefore t=0 satisfies the other equation

Finding the tangent vector at t=0

$\frac{dx}{dt}=-2te^{-2t} cos4t + e^{-2t}(-4sin4t)=-2(0)e^{-2(0)} cos4(0) + e^{-2(0)}(-4sin4(0))=0\\\\ \frac{dy}{dt} =-2te^{-2t} sin4t + e^{-2t}(4cos4t)=-2(0)e^{-2(0)} sin4(0)+ e^{-2(0)(4cos4(0)) }= 1\\\\\frac{dz}{dt} = -2te^{-2t} = -2(0)e^{-2(0)} = 0$

The vector equation of the tangent line is

(1, 0, 1) +s(0,1,0)= (1, s, 1)

The parametric equations are:

x=1

y=s

z=1

6 0

3 years ago

A kitchen floor has 15 1/2 tiles in an area of 2 2/5 square feet. How many tiles are in one square foot?

Marat540 [252]

6 2/5 is the answer, because 15 1/2 divided by 2 2/5 is 6 2/5

6 0

3 years ago

What is the equation of the line in point slope form given a slope of -3 and a point of (-2,-5)?

Lelu [443]

Answer:

y = -3x - 11

Step-by-step explanation:

Use the given slope and point in the point-slope equation. Solving this will give us the y-intercept equation.

Point-slope formula: y - y = m(x - x)

Plug in the slope and point

y - (-5) = -3(x - (-2))

Subtracting negatives will make them positive. Multiply out the -3 to what is in the parentheses.

y + 5 = -3x - 6

Subtract the 5 from both sides

y = -3x - 11

The equation of the line is y = -3x - 11

7 0

2 years ago