You run a 100-yd dash in 9.8 seconds. how long would it take you to run a 100-m dash if you run at this same speed?

Part 1: Use the information provided to write the standard form equation of each circle. Please show the work.

dusya [7]

Answer:

1. (x + 2)² + (y - 9)² = 64

2. (x + 6)² + (y - 9/2)² = 100

3. (x - 15)² + (y + 10)² = 1

Step-by-step explanation:

Equation of a circle:

(x - h)² + (y - k)² = r²

1. Center: (-2, 9), Radius: 8

(x - (-2))² + (y - 9)² = 8²

(x + 2)² + (y - 9)² = 64

2. Center: (-6, 9/2), Radius: 10

(x - (-6))² + (y - (9/2))² = 10²

(x + 6)² + (y - 9/2)² = 100

3. Center: (15, -10), Radius: 1

(x - 15)² + (y - (-10))² = 1²

(x - 15)² + (y + 10)² = 1

4 0

3 years ago

(8,10) (-7,14) find the slope of the line through each pair of points.

DochEvi [55]

Slope is rise over run which is -4/15

8 0

2 years ago

Read 2 more answers

Help please if you can

r-ruslan [8.4K]

Answer:

i cant

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Evaluate the indefinite integral. <br> integar x4/1 + x^10 dx

ivann1987 [24]

Answer:

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx = \frac{1}{5}( \arctan(x^5)) + c$

Step-by-step explanation:

Given

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx$

Required

Integrate

We have:

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx$

Let

$u = x^5$

Differentiate

$\frac{du}{dx} = 5x^4$

Make dx the subject

$dx = \frac{du}{5x^4}$

So, we have:

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx$

$\int\ {\frac{x^4}{1 + x^{10}}} \, \frac{du}{5x^4}$

$\frac{1}{5} \int\ {\frac{1}{1 + x^{10}}} \, du$

Express x^(10) as x^(5*2)

$\frac{1}{5} \int\ {\frac{1}{1 + x^{5*2}}} \, du$

Rewrite as:

$\frac{1}{5} \int\ {\frac{1}{1 + x^{5)^2}}} \, du$

Recall that: $u = x^5$

$\frac{1}{5} \int\ {\frac{1}{1 + u^2}}} \, du$

Integrate

$\frac{1}{5} * \arctan(u) + c$

Substitute: $u = x^5$

$\frac{1}{5} * \arctan(x^5) + c$

Hence:

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx = \frac{1}{5}( \arctan(x^5)) + c$

7 0

2 years ago

Look at picture please worth 15 points please helpppp

sergij07 [2.7K]

Answer:

3x - y + $\frac{- 5x^2y}{3x^3 + 2x^2y - xy^2}$

Step-by-step explanation:

Hooboy okay here we go.

1.) Rewrite the equation in the classic division method

3x³ + 2x²y - xy² $\sqrt{9x^4 + 3x^3y - 5x^2y^2 + xy^3}$

2.) Divide using normal division rules, but it's super hard now 'cause there are letters involved. Basically, what can you multiply 3x³ by to get 9x⁴? 3x. So 3x is your first number. Then multiply everything else by 3x, and subtract

3x

3x³ + 2x²y - xy² $\sqrt{9x^4 + 3x^3y - 5x^2y^2 + xy^3}$

-(9x⁴ + 6x³y - 3x²y²)

= 0 - 3x³y - 2x²y² - 5x²y + xy³

Now lets do that again, see what happens. 3x³ times -y should get -3x³y

3x - y

3x³ + 2x²y - xy² $\sqrt{9x^4 + 3x^3y - 5x^2y^2 + xy^3}$

- (9x⁴ + 6x³y - 3x²y²)

= 0 - 3x³y - 2x²y² - 5x²y + xy³

- ( - 3x³y - 2x²y² + xy³)

= 0 + 0 - 5x²y + 0

So! From this information, we can know that the answer is 3x-y with a remainder of - 5x²y. How it's written is shown above, in "Answer"

3 0

2 years ago