Do do this, you use the distance formula: time * speed = distance
So you do, 4.9 * 15.5 = 75.95
So, the rover will travel <u>75.95 centimeters</u> in 15.5 seconds at a speed of 4.9 cm./s
f(n) is the nth term
Each term f(n) is found by adding the terms just prior to the nth term. Those two terms added are f(n-1) and f(n-2)
The term just before nth term is f(n-1)
The term just before the (n-1)st term is f(n-2)
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For example, let's say n = 3 indicating the 3rd term
n-1 = 3-1 = 2
n-2 = 3-2 = 1
So f(n) = f(n-1) + f(n-2) turns into f(3) = f(2) + f(1). We find the third term by adding the two terms just before it.
f3) = third term
f(2) = second term
f(1) = first term
<h3>
Answer: 6 inches</h3>
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Explanation:
x = amount (in inches) the spring is stretched
y = force applied (in pounds)
y = kx for some constant k, since x and y vary directly
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Plug in the given info that x = 5 and y = 150 pair up together
Solve for k
150 = k*5
150/5 = k
k = 30
The equation goes from y = kx to y = 30x. Whatever the stretching distance (x) is, you multiply by 30 to get the force needed (y) to pull the spring.
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Plug in y = 180 to solve for x
y = 30x
180 = 30x
30x = 180
x = 180/30
x = 6
The spring will be stretched 6 inches if you apply a force of 180 pounds.
So, start with the growth formula
A=P(1+r)^t then plug in the values
6200=5200(1+.038)^t
then divide both sides by 5200
1.1923076923=1.038^t
then take the log of both sides
log(1.1923076923)= t log(1.038)
then divide both sides by the log(1.038)
4.7161004299=t
then round it to the nearest whole number
5=t
so about 5 months