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WARRIOR [948]
3 years ago
10

Please help! ASAP plz<3

Mathematics
1 answer:
leva [86]3 years ago
7 0
What do you need help with ASAP?
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In a sample of 679 new websites registered on the Internet, 42 were anonymous (i.e., they shielded their name and contact inform
Semmy [17]

Answer:

95% Confidence interval:  (0.0429,0.0791)      

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 679

Number of anonymous websites, x = 42

\hat{p} = \dfrac{x}{n} = \dfrac{42}{679} = 0.0618

95% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96

Putting the values, we get:

0.0618\pm 1.96(\sqrt{\dfrac{0.0618(1-0.0618)}{679}}) = 0.0618\pm 0.0181\\\\=(0.0429,0.0791)

is the required confidence interval for proportion of all new websites that were anonymous.

8 0
3 years ago
John has gross biweekly earnings of $743.61. By claiming 1 more withholding allowance, John would have $19 more in his take home
Afina-wow [57]

Answer:

Total withholding allowances are 39.

Step-by-step explanation:

Given the gross earning of John = $743.61

It is given that 1 withholding allowance = $19

Now we have to find the total number of withholding allowances. Here, the number of withholding allowances can be determined by dividing the total earnings with $19.

Number of withholding allowances = 743.61 / 19 = 39.14 or 39 (round off).

4 0
3 years ago
Write he ratio that compares $7 1/2 dollars to 3/4 pound of coffee dollars to pounds of coffee=
Anna35 [415]
You would multiply both and then the answer you would put into ratio form
8 0
3 years ago
Please help with the this give tiny explanation
Mila [183]

Answer:

21

first we begin from 1 to 100 we find 11 numbers contain 1 then we count 1s from 10 to 19 we get 9 numbers but there is an exciption in number 11 as it cotains 2 1s so thenumber of 1s is 21

5 0
3 years ago
The mean (average) weight of three dogs is 38 pounds. One of the dogs, Shaggy, weighs
Readme [11.4K]
I honestly do not know this seems to me to be a trick question
5 0
2 years ago
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