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Tom [10]
3 years ago
11

Evaluate the expression 27/j for j=3

Mathematics
1 answer:
STALIN [3.7K]3 years ago
3 0
27 divided by 3 (j) is 9. If j=3 then plug in 3 for the equation
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Which equation is equivalent to (1/3)^x=27^x+2?
ruslelena [56]
Ok so the answer is D because first I solved the equation because you can’t find which answer choice it is equivalent to if you didn’t solve it ... so I solved the equation and got x=-3/2 how I solved this is

3^-x = 3^3x+6 ... since the bases are the same, set the exponents equal
-x=3x+6..... move the variable to the left-hand side and change its side
-x-3x=6 ... collect like terms
-4x = 6..... divide both sides of the equation by -4 and I got x=-3/2
I don’t want this text to be that long so they both seem calculated the same way that’s why i got -3/2 hope that helps;-;
6 0
3 years ago
A bottle of apple juice cost $.89 what is the total cost of 5 cartons of apple juice if there are 12 bottles in each carton
stiks02 [169]
12 x .89 = 10.68
10.68 x 5= $53.40
answer is $53.40
3 0
3 years ago
Who's excited for Christmas?!?! :D<br> if not why?
Pie
I’m very excited, I get to see my brothers so that’s fun
3 0
2 years ago
You are going to draw two candy bars from a large bag containing 28 snickers bars and 5 twix bars. what is the probability that
amm1812
Find the probability of drawing 1 snicker first then the probability of drawing another snicker after that, then multiply them together. For the first choice, the probability of drawing a Snickers is 28/33 (snickers/total candy bars). For the second choice, there are only 32 candy bars left, 27 of which are Snickers. So that probability is 27/32, so...
The probability of BOTH things happening is their product 756/1,056 which is 63:88
6 0
3 years ago
Which equation has the solutions x = 1+
BaLLatris [955]

Answer:

The last equation x2 - 2x -4 = 0

has solution  (x - 1)^2 - 5 = 0,   x  =  1 + root(5)  or  x = 1 - root(5)

Step-by-step explanation:

If a quadratic function has roots 1 and 5

f(x) = (x -1)(x- 5)

f(x) = x^2 - 6x + 5

Unless you meant.  -4 and 6  ?

g(x) = (x + 4)(x - 6)

g(x) = x^2 -2x -24

-------------------------

Or did you mean  x = 1 and x =4 ?...

x^2 + 2x + 4 = 0  :   complete square  x^2 + 2x + 1 + 3 = 0,   (x+1)^2 + 3 = 0

x^2 - 2x + 4 = 0 :  complete square:  (x -1)^2 + 3 = 0

0x^2 + 2x - 4 = 0,    2x - 4 = 0,  x = 2

x^2 - 2x - 4 = 0  becomes:   x^2 - 2x + 1 - 1 -4 = 0 ;  (x - 1)^2 - 5 = 0

5 0
3 years ago
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