Answer:
uuyjj+jjh6688292837363627
prank hahahaha
Step-by-step explanation:
8282772627292929383
2828892
283933
38833
8282828
prank hahahha
Step-by-step explanation:
a=5*-4*-3
a=-2
hope this helps
Answer:
<u>~Senpi boi here~</u>
Step-by-step explanation:
Multiply all terms by x and cancel:
x+2x+1=1x
3x+1=x(Simplify both sides of the equation)
3x+1−x=x−x(Subtract x from both sides)
2x+1=0
2x+1−1=0−1(Subtract 1 from both sides)
2x=−1
2x
2
=
−1
2
(Divide both sides by 2)
x=
−1
2
Check answers. (Plug them in to make sure they work.)
x=
−1
2
(Works in original equation)
<u>Answer:</u>
<u>x= −1/2</u>
<u>(</u>Hope this helps!)
Step-by-step explanation:
slope(m)= y2-y1/x2-x1
-2-6/4+2
= -8/6
= -4/3
Answer:
a) 72.25sec
b) 6.25secs
c) after 10.5secs and 2 secs
Step-by-step explanation:
Given the height reached by the rocket expressed as;
s(t)= -4t^2 + 50t - 84
At maximum height, the velocity of the rocket is zero i.e ds/dt = 0
ds/dt = -8t + 50
0 = -8t + 50
8t = 50
t = 50/8
t = 6.25secs
Hence it will reach the maximum height after 6.25secs
To get the maximum height, you will substitute t - 6.25s into the given expression
s(t)= -4t^2 + 50t - 84
s(6.25) = -4(6.25)^2 + 50(6.25) - 84
s(6.25) = -156.25 + 312.5 - 84
s(6.25) = 72.25feet
Hence the maximum height reached by the rocket is 72.25feet
The rocket will reach the ground when s(t) = 0
Substitute into the expression
s(t)= -4t^2 + 50t - 84
0 = -4t^2 + 50t - 84
4t^2 - 50t + 84 = 0
2t^2 - 25t + 42 = 0
2t^2 - 4t - 21t + 42 = 0
2t(t-2)-21(t-2) = 0
(2t - 21) (t - 2) = 0
2t - 21 = 0 and t - 2 = 0
2t = 21 and t = 2
t = 10.5 and 2
Hence the time the rocket will reach the ground are after 10.5secs and 2 secs
