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bearhunter [10]
3 years ago
10

A loan of $12,000 is made at 5.25% interest, compounded annually. After how many years will the amount due reach $22,000 or more

?
Mathematics
1 answer:
yaroslaw [1]3 years ago
6 0

Answer:

About 16 years

Step-by-step explanation:

First we need to figure out 5.25% of 12000

5.25 x 0.12000 = 0.63

Then we move the decimal

630

Then we need to figure out how many years it will take to reach $22000

Since we already owe $12000, we can just divide using $10000 because 10000 + 12000 = 22000

10000/630 = 15.87

Which is about 16 years

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Find for the following functions. f(x) = 12x2 + 7x + 2 g(x) = 9x + 7
erastova [34]

Answer:

I Believe your answer is 12x2+16x+9

if not, be more specific for what you need, I will be glad to answer

Step-by-step explanation:

One of the following functions is made of a composition of f(x) and g(x)

12x2 + 16x + 2

21x3 + 14x + 2

12x2 + 16x + 9

21x2 + 14x + 2

If we sum f(x) with g(x) we have the answer 12x2+16x+9

Perfoming another operation like f(x)*g(x), f(x)-g(x), f(g(x)), doesnt give anything like the below functions.

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3 years ago
Hoping to lure more shoppers downtown, a city builds a new public parking garage in the central district. The city plans to pay
andrezito [222]

Answer:

a) For this case we need to use a t distribution since we know the information about a sample and we don't know the population deviation.

b) 126-1.77\frac{15}{\sqrt{14}}=118.904    

126+1.77\frac{15}{\sqrt{14}}=133.096    

So on this case the 90% confidence interval would be given by (118.904;133.096)

c) For this case since confidence interval include tha value of 130 so then we don't have enough evidence to conclude that the claim by the consultant is incorrect.    

Step-by-step explanation:

Part a

For this case we need to use a t distribution since we know the information about a sample and we don't know the population deviation.

Part b

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

\bar X=126 represent the sample mean

\mu population mean (variable of interest)

s=15 represent the sample standard deviation

n=14 represent the sample size  

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=14-1=13

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,13)".And we see that t_{\alpha/2}=1.77

Now we have everything in order to replace into formula (1):

126-1.77\frac{15}{\sqrt{14}}=118.904    

126+1.77\frac{15}{\sqrt{14}}=133.096    

So on this case the 90% confidence interval would be given by (118.904;133.096)

Part c

For this case since confidence interval include tha value of 130 so then we don't have enough evidence to conclude that the claim by the consultant is incorrect.    

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Answer:

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20 points and giving a brainiest who answers correctly.
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