Answer:
20 meters
Step-by-step explanation:
The track is circular so it means that after Patrick raced the entire track he is back at the starting point. In other words, every 440 meters he is back to the beginning.
So we would have that, if he races round the track twice, he would run 440(2) = 880 meters and he would be back at the starting point.
The problem asks us how far is he from the starting point at the 900 meter mark. If at 880 meters he is at the starting point, then at 900 meters he would be 
meters from the starting point.
Area = side AB * side BC = (5x + 5x + 3)(3x + 92x - 4)
= (10x + 3)(95x - 4) = 950x^2 - 40x + 285x - 12
= 950x^2 + 245x - 12 Answer
This cannot be negative so restriction on x is 950x^2 + 245x > 12
That is x > 0.0421
Answer:
-36x^2+1
Step-by-step explanation:
(1+6x)(1-6x)
= 1^2(6x)^2
= -36x^2+1
Answer:
The scaled surface area of a square pyramid to the original surface area.
The scaled area of a triangle to the original area.
Step-by-step explanation:
Suppose that we have a cube with sidelength M.
if we rescale this measure with a scale factor 8, we get 8*M
Now, if previously the area of one side was of order M^2, with the rescaled measure the area will be something like (8*M)^2 = 64*M^2
This means that the ratio of the surfaces/areas will be 64.
(and will be the same for a pyramid, a rectangle, etc)
Then the correct options will be the ones related to surfaces, that are:
The scaled surface area of a square pyramid to the original surface area.
The scaled area of a triangle to the original area.
Answer: the Answer is b
Step-by-step explanation:
