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Sever21 [200]
3 years ago
8

(-8x⁴y³)(2x⁵y²)+7x⁹y⁵

Mathematics
2 answers:
LenaWriter [7]3 years ago
8 0

Answer:

ss

Step-by-step explanation:

STatiana [176]3 years ago
8 0

Answer:

-9x^{9} y^{5}

Step-by-step explanation:

(-8x⁴y³)(2x⁵y²)+7x⁹y⁵  (grouping like terms)

= (-8)(2) (x⁴x⁵) (y³y²) +7x^{9} y^{5}

= -16 x^{4+5} y^{3+2 } + 7x^{9} y^{5}

= -16 x^{9} y^{5} + 7x^{9} y^{5}

= (-16 + 7)x^{9} y^{5}

= -9x^{9} y^{5}

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Answer:

<h2>cosecθ = 1/sinθ = 11/6√2</h2>

Step-by-step explanation:

Given that  cos θ =7/11, cosec θ = 1/sinθ in trigonometry.

Based on SOH, CAH, TOA;

cosθ = adjacent/hypotenuse = 7/11

adjacent = 7 and hyp = 11

Since sinθ = opp/hyp, we need to get the opposite to be able to calculate sinθ.

Using pythagoras theorem to get the opposite;

hyp^{2} = adj^{2}  + opp ^{2}  \\opp = \sqrt{hyp^{2} - adj^{2}  } \\opp = \sqrt{11^{2} - 7^{2}} \\opp = \sqrt{72} \\opp = 6\sqrt{2}

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cosecθ = 1/sinθ = 11/6√2

Note the error; cscθ\neq 1/cosθ but cscθ = 1/sinθ

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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Read 2 more answers
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