To find out the number of real solutions, we use something called "the discriminant". This is usually given the symbol "<span>Δ", pronounced "delta"
</span><span> Δ = b^2 - 4ac, where a is the x^2 coefficient, b is the x coefficient and c is the integer
</span>
When Δ = 0, there is one real solution, when Δ < 0, there are no real solutions, and when Δ > 0, there are 2 real solutions
So, substituting the values in, we get:
Δ = (20)^2 - 4(-4)(-25) = 0
Therefore, there is one real solution to the polynomial given.
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Answer:
(D) -k2 + k - 13
Step-by-step explanation:
Pulling out like terms :
2.1 Pull out like factors :
-k2 + k - 13 = -1 • (k2 - k + 13)
Trying to factor by splitting the middle term
2.2 Factoring k2 - k + 13
The first term is, k2 its coefficient is 1 .
The middle term is, -k its coefficient is -1 .
The last term, "the constant", is +13
Step-1 : Multiply the coefficient of the first term by the constant 1 • 13 = 13
Step-2 : Find two factors of 13 whose sum equals the coefficient of the middle term, which is -1 .
-13 + -1 = -14
-1 + -13 = -14
1 + 13 = 14
13 + 1 = 14
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
-k2 + k - 13
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Step-by-step explanation:
I write it in the pic.I hope that I undrestand what you mean
Answer:
(c) -6 is the correct option.
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A, C would be my best guesses