All categories

4 years ago

It is warmer at the equator than at 80° N because _____.

Biology

2 answers:

Zina [86]4 years ago

8 0

Equator receives sunlight at a direct angle front the sun than other planets

Nana76 [90]4 years ago

5 0

Answer:

Explanation:

You might be interested in

The bones from an animal found at an archaeological dig have a C614 activity of 0.10 Bq per gram of carbon. The half-life of C61

erastova [34]

C14 is an isotope used in radiocarbon dating techniques to date organic matter remains. The age of these bones is approximately 6890 years.

<h3>What is Carbon 14?</h3>

Carbon 14, also known as radiocarbon, is a radioactive carbon isotope.

Isotopes are the atoms of the same element -carbon- that vary in neutrons and, hence, in their massic number. They are alternative forms of the same element.

The radioactive C14 nucleus contains 6 protons and 8 neutrons and has a half-life of 5730 years.

The term half-life is a reference. It means that an organism that has been dead for 5730 years has half the C14 amount or concentration than the same organism had when it was alive.

Knowing the half-life of an element is useful to determine the age of the dead matter.

C14 is used in radiocarbon dating techniques or methods to estimate the age of fossils. This is a reliable technique used for dating organic samples that are less than 50,000 years old.

Available data:

The half-life of C14 is 5730 years
Bones activity of 0.10 Bq per gram of carbon

To answer this question we can make use of the following equation

Ln (C14T₁/C14 T₀) = - λ T₁

Where,

C14 T₀ ⇒ Amount of carbon in a living body. We know, by bibliography, that living organism activity is 0.23 Bq per gram of carbon. So, C14 T₀ = 0.23 Bq/g

C14T₁ ⇒ Amount of carbon in the dead body. C14T₁ = 0.1 Bq/g

λ ⇒ radioactive decay constant = (Ln2)/T₀,₅

T₀,₅ ⇒ The half-life of carbon 14 = 5730 years

T₀ = Time when the organism was alive

T₁ = Age of bones

Let us first calculate the radioactive decay constant.

λ = (Ln2)/T₀,₅

λ = 0.693/5730

λ = 0.0001209

Now, let us calculate the first term in the equation

Ln (C14T₁/C14 T₀) = Ln (0.1/0.23) = Ln 0.4347 = - 0.833

Finally, let us replace the terms, clear the equation, and calculate the value of T₁.

Ln (C14T₁/C14 T₀) = - λ T₁

- 0.833 = - 0.0001209 x T₁

T₁ = - 0.833 / - 0.0001209

T₁ = 6889.99 ≅ 6890 years

The bones are approximately 6890 years.

You can learn more about dating organic matter with carbon14 at

brainly.com/question/4149380

#SPJ1

6 0

3 years ago

ArbitrLikvidat [17]

Answer: C

Explanation: stage v is where the daughter cells split, and must be the final stage, because the process repeats itself after they split.

6 0

3 years ago

What’s the answer ?????????????

aev [14]

Answer:

cvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvExplanation:

8 0

3 years ago

This element is the only metal found along the zig zag line

elixir [45]

are found along the zigzag line on the periodic table. The only exception is Aluminum. It is considered to be a metal even though it lies along the zigzag.

6 0

3 years ago

A written dialogue, from your perspective as the nucleus, explaining the parts of the cell to your mentee.

Varvara68 [4.7K]

The Cell to Mentee

A cell is the basic unit of life of a human. The body cell contains cytoplasm in which organelles are present . There is a nucleus found in eukaryotic cell. It contains the genetic material in the form of DNA with proteins and chromosomes. Inside there is nuclear membrane. Outside the nucleus, there are many other organelles like mitochondria, ribosomes, golgi apparatus, endoplasmic reticulum, and many more.

8 0

3 years ago