Answer:
D. 
Step-by-step explanation:
Let be ![y = \Sigma_{i = 0}^{4} \left[5\cdot \left(\frac{1}{3} \right)^{i}\right]](https://tex.z-dn.net/?f=y%20%3D%20%5CSigma_%7Bi%20%3D%200%7D%5E%7B4%7D%20%5Cleft%5B5%5Ccdot%20%5Cleft%28%5Cfrac%7B1%7D%7B3%7D%20%5Cright%29%5E%7Bi%7D%5Cright%5D)
. To find the equivalent expression we must use the following property:
![y = c\cdot \Sigma_{i = 0}^{n} p(x) = \Sigma_{i=0}^{n} [c\cdot p(x)]](https://tex.z-dn.net/?f=y%20%3D%20c%5Ccdot%20%5CSigma_%7Bi%20%3D%200%7D%5E%7Bn%7D%20p%28x%29%20%3D%20%5CSigma_%7Bi%3D0%7D%5E%7Bn%7D%20%5Bc%5Ccdot%20p%28x%29%5D)
(1)
Based on this fact, we find the following equivalence:
Hence, the correct answer is D.
Answer: c
Step-by-step explanation:
bc
-2° was the initial temperature as it dropped to -5°
-2-5=-7
Hope this helped
Answer:
m=88
Step-by-step explanation:
First we have to isolate the variable. In this case, it would be by multiplying the reciprocal of the fraction the both sides. M will be alone and the other side should come out to be 88. Assuming you know how to multiply with fractions, of course.
Answer:
x² + 4xy + 4y²
Step-by-step explanation:
(x + 2y)² = (x + 2y)(x + 2y)
Each term in the second factor is multiplied by each term in the first factor
(x + 2y)(x + 2y)
= x(x + 2y) + 2y(x + 2y) ← distribute both parenthesis
= x² + 2xy + 2xy + 4y² ← collect like terms
= x² + 4xy + 4y²
