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tankabanditka [31]
3 years ago
10

The distance d of a particle moving in a straight line is given by d(t) = 2t3 + 5t – 2, where t is given in seconds and d is mea

sured in meters. Find an expression for the instantaneous velocity v(t) of the particle at any given point in time. Question 1 options: 6t3 – 5 5t3 + 6 6t2 + 5 5t2 – 6
Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
6 0

Answer:

(C)6t^2+5

Step-by-step explanation:

Given the distance, d(t) of a particle moving in a straight line at any time t is:

d(t) = 2t^3 + 5t - 2, $ where t is given in seconds and d is measured in meters.

To find an expression for the instantaneous velocity v(t) of the particle at any given point in time, we take the derivative of d(t).

v(t)=\dfrac{d}{dt}\\\\v(t) =\dfrac{d}{dt}(2t^3 + 5t - 2) =3(2)t^{3-1}+5t^{1-1}\\\\v(t)=6t^2+5

The correct option is C.

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Jordan's recipe calls for 3 cups of flour and 2 cups of water. what is the ratio of flour to water? if jordan wants to triple hi
allochka39001 [22]
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PLEASE I NEED HELP! How do you find y?
myrzilka [38]

In this example, y is equal to 8.

In order to find this, first note that the two x value expressions create a straight line. That means when we add them together they will equal 180. this will give us a value for x.

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3 years ago
(5.6x - 4) + (16 - 2.1x)<br><br> What is the sum of this expression?
Damm [24]

\huge\text{Hey there!}

\large\textsf{(5.6x - 4) + (16 - 2.1x)}

\large\text{DROP the PARENTHESES}

\large\textsf{5.6x - 4 + 16 - 2.1x}

\large\text{COMBINE the LIKE TERMS}

\large\textsf{5.6x - 2.1x - 4 + 16}

\large\textsf{5.6x - 2.1x = \bf  3.5x}

\large\textsf{-4 + 16 = \bf  12}

\large\textsf{=  \bf 3.5x + 12 }

\boxed{\boxed{\large\text{Answer: \huge \bf 3.5x + 12}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

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