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Andrew [12]
4 years ago
12

The flagpole is 20 ft high and casts an 8 foot shadow, the oak tree casts a 12 foot shadow. How tall is the oak tree

Mathematics
1 answer:
Fudgin [204]4 years ago
7 0
Answer: 4.8 ft

To answer this question you need to know how much shadow: actual height ratio. Flagpole is having 8 ft shadow with 20 ft actual height. The ratio should be= 8 ft: 20 ft= 0.4

Then multiply the ratio with the oak tree shadow. The equation would be:
0.4 x 12 ft= 4.8 ft  
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There is a proportional relationship between the volume of a sample of helium in liters and the mass of that sample in grams. if
love history [14]

Answer:

  • v = 5.6m

Step-by-step explanation:

<u>Proportional relationship equation:</u>

  • y = kx, where k- constant of proportionality

<u>Use the given point to work out the value of k:</u>

  • 28 = 5k
  • k = 28/5
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<u>In our case the equation is:</u>

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6 0
2 years ago
Look at the figure. Which step should be taken next to construct a line through point P perpendicular to BA?
alexira [117]

ANSWER:

C. Place the compass on point A. Open the compass to a point between point P and point B.

EXPLANATION:

A perpendicular is a line that would be at a right angle to line BA.

The next step is to chose a radius that is greater than PB or PA so as to construct the bisector. And this can be done by placing the compass on point A, and open the compass to a point between point P and point B.

Use this radius to draw an arc above and below the line, and repeat the same using B as the center with the same radius. This would form two intersecting arcs above and below line BA. Join the point of intersection of the arcs by a straight line through P. This is the bisector of line BA through point P.

8 0
3 years ago
Which of these expressions CANNOT be simplified by combining like terms?
densk [106]
5ab^{3} +7-3a^{2} b ^{2} +a^{3}b+10 can be simplified to by adding the 7 and 10 to get a^{3}b-3a^{2} b ^{2}+ 5ab^{3} + 17.

5ab^{3}+3a^{2}b^{2}+a^{3}b -10 cannot be simplified any more by combining like terms.

By distributing the 2b into the parentheses, you can simplify the expression:
5ab^{3}+2b(3ab^{2})+a^{3}b-10\\&#10;5ab^{3}+6ab^{3}+a^{3}b-10\\&#10;11ab^{3}+a^{3}b-10

Here you can just add:
5a^{3}b^{3}+3a^{2}b^{2}+a^{3}b^{3}-10ab\\&#10;6a^{3}b^{3}+3a^{2}b^{2}-10ab

Thus, the only expression that cannot simplify any more using adding like terms is the second, 5ab^{3}+3a^{2}b^{2}+a^{3}b -10.
3 0
3 years ago
Read 2 more answers
QS¯¯¯¯¯¯¯ bisects ∠PQR . If m∠PQS = 5x and m∠RQS = 2x + 6, then what is m∠PQR ? m∠PQR is
soldi70 [24.7K]

Answer:

PQR = 20

Step-by-step explanation:

Given

Bisector: QS

PQS = 5x

RQS = 2x + 6

Required

Determine PQR

Since PQR is bisected to PQS and RQS, we have that

PQS = RQS

Substitute expressions for PQS and RQS

5x = 2x + 6

Collect Like Terms

5x - 2x = 6

3x = 6

Divide both sides by 3

x = 2

Solving for PQR;

PQR = PQS + RQS

PQR = 5x + 2x + 6

PQR = 7x + 6

Substitute 2 for x

PQR = 7 * 2 + 6

PQR = 14 + 6

PQR = 20

4 0
3 years ago
Rob is twice Joshua's age. Nick is 5 years older than Joshua. The sum of all their ages is 45. How old is Nick?
MatroZZZ [7]

Given

Rob is twice Joshua's age

Nick is 5 years older than Joshua.

sum of all their ages is 45.

Find the age of nick.

To proof

As given

Rob is twice Joshua's age

let  Joshua's age = x

than Rob age = 2x

Nick is 5 years older than Joshua.

Nick age = 5 + x

sum of all their ages is 45

than the equation becomes

Joshua's age + Rob age + Nick age = 45

put the value

x + 2x + 5 + x = 45

4x = 40

x = 10

Joshua's age = 10 year

than Rob age = 20 year

Nick age = 5 + 10

                = 15year

Hence proved


6 0
3 years ago
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