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Svetlanka [38]
3 years ago
9

My someone pls help me

Mathematics
1 answer:
AnnZ [28]3 years ago
7 0

Answer:

No its not a proportion, the numerators can't be divided evenly

Step-by-step explanation:

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yanalaym [24]

Answer:

\frac{f(x+h)-f(x)}{h}=2x + h

Step-by-step explanation:

Given

f(x)= x^2 + 2

Required

Determine: \frac{f(x+h)-f(x)}{h}

First, we calculate f(x + h)

f(x)= x^2 + 2

f(x+h) = (x+h)^2+2

f(x+h) = x^2+2xh+h^2+2

So, we have:

\frac{f(x+h)-f(x)}{h} = \frac{x^2 + 2xh + h^2 + 2 - x^2 - 2}{h}

\frac{f(x+h)-f(x)}{h}= \frac{x^2 - x^2+ 2xh + h^2 + 2  - 2}{h}

\frac{f(x+h)-f(x)}{h} = \frac{2xh + h^2}{h}

\frac{f(x+h)-f(x)}{h}=2x + h

8 0
2 years ago
Each of the following data sets has a mean of x = 10. (i) 8 9 10 11 12 (ii) 7 9 10 11 13 (iii) 7 8 10 12 13 (a) Without doing an
stepladder [879]

Answer:

Step-by-step explanation:

Given are 3 data sets with values as:

(i) 8 9 10 11 12   ... Mean =10

(ii) 7 9 10 11 13    ... Mean =10

(iii) 7 8 10 12 13   ... Mean =10

We see that  data set shows mean deviations as

(i) -2 -1 0 1 2  

(ii) -3 -1 0 1 3    

(iii) -3 -2 0 2 3  

Since variance is the square of std deviation, we find that std deviation is larger when variance is larger.

Variance is the sum of squares of (x-mean).  Whenever x-mean increases variance increases and also std deviation.

Hence we find that without calculations also (i) has least std dev followed by (ii) and then (iii)

(i) (ii) (iii) is the order.

b) Between (i) and (ii) we find that 3 entries are the same and 2 entries differ thus increasing square by 9-4 twice.  But between (ii) and (iii) we find that

increase in square value would be 4-1 twice. Obviously the latter is less.

6 0
3 years ago
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