Answer:
21 ft by 66 ft
Step-by-step explanation:
From the question,
P = 2(L+W)............... Equation 1
Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.
If the Length of the Field is 45 ft longer than the width,
L = 45+W............ Equation 2
Substitute Equation 2 into equation 1
P = 2(45+W+W)
P = 90+4W............. Equation 3
Given: P = 174 ft.
Substitute into equation 3
174 = 90+4W
4W = 174-90
4W = 84
W = 84/4
W = 21 ft.
Substituting the value of W into equation 2
L = 45+21
L = 66 ft.
Hence the dimensions of the playing field is 21 ft by 66 ft
The total would be 180 degrees because angles on a straight line would always add up to 180.
(3x+31)+(2x-6)=180
5x+25=180
-25 -25
5x=155
/5 /5
x=31
Answer: g = 1
Step-by-step explanation:
-3 + 5 + 6g = 11 - 3g
First, we need to combine like terms
-3 + 5 = 2
2 + 6g = 11 - 3g
Add 3g to each side
2 + 9g = 11
Subtract 2 from each side
9g = 9
Divide each side by 1
g = 1
